Ask question

Ask question

All categories

3 years ago

14

Tell whether the following set is an empty set or not.

2 answers:

Liono4ka [1.6K]3 years ago

7 0

Answer:

It is not an empty set

Step-by-step explanation:

A quadrilateral with 3 obtuse angles is possible.

A obtuse angle has a measure of more than 90 degrees and less than 180 degrees.

Let’s say three angles are measuring 91 degrees in a quadrilateral.

91 + 91 + 91 + x = 360

x = 87

The measure of the fourth angle is 87 degrees which is less than 360 degrees and is a positive integer, so it is possible.

igor_vitrenko [27]3 years ago

4 0

Answer:

It is not an empty set

Step-by-step explanation:

Obtuse angles are angles greater than 90 and less than 180.

There are quadrilaterals having 3 obtuse angles and they are possible.

If we imagine 3 obtuse angles of 91 degrees (obtuse angle), the 4th angle will be

360-91-91-91

=> 87 degrees

So, This quadrilateral can be constructed!

And also with 92, 93, 94 and so on!

So, Set A is not an empty set!

You might be interested in

Solve the proportion 20/16=X/80<br><br> A=6.25<br> B=1600<br> C=100<br> D=160

mamaluj [8]

C. 100 is the aswer i thinck

7 0

3 years ago

i have 44 followers and my friend has 4 dollars. Then count the mass of followers on all social media and the mass of money earn

drek231 [11]

Answer:

Purple

Step-by-step explanation:

3 0

3 years ago

Hey Bestie! 50 pts Pls help! Real answers only pls <3

frosja888 [35]

Answer:

$1. \: 3i$

2. option D

3. option C

4. option D

5. option C

6. option B

7. option C

8. option D

9. option C

10. option C

Step-by-step explanation:

<h2> $1. \: \sqrt{ - 9}$ </h2>

$\sqrt{ - 1(9)}$

$\sqrt{ - 1} \times \sqrt{ 9}$

$i \times \sqrt{9}$

$i \times \sqrt{ {3}^{2} }$

$i \times 3$

$3i$

<h2> $2. \: \sqrt{ - 8}$ </h2>

$\sqrt{ - 1(8)}$

$\sqrt{ - 1} \times \sqrt{8}$

$i \times \sqrt{8}$

$i \times \sqrt{ {2}^{2} \times 2 }$

$2i \sqrt{2}$

<h2> $3. \: \sqrt{ - 80}$ </h2>

$\sqrt{ - 1} \times \sqrt{80}$

$i \times \sqrt{80}$

$4i \: \sqrt{5}$

<h2> $4. \: \sqrt{ - 75}$ </h2>

$\sqrt{ - 1} \times \sqrt{75}$

$i \times \sqrt{75}$

$i \times \sqrt{ {5}^{2} \times 3 }$

$5i \sqrt{3}$

<h2> $5. \: \sqrt{ - 72}$ </h2>

$\sqrt{ - 1} \times \sqrt{72}$

$i \times \sqrt{72}$

$i \times ( {6}^{2} \times 2)$

$6i \sqrt{2}$

<h2> $6. \sqrt{ - 20}$ </h2>

$\sqrt{ - 1} \times \sqrt{20}$

$i \times \sqrt{20}$

$i \times \sqrt{ {2}^{2} \times 5}$

$2i \sqrt{5}$

<h2> $7. \: \sqrt{ - 27}$ </h2>

$\sqrt{ - 1} \times \sqrt{27}$

$i \times \sqrt{27}$

$i \times \sqrt{ {3}^{2} \times 3}$

$3i \sqrt{3}$

<h2> $8. \: \sqrt{ - 12}$ </h2>

$\sqrt{ - 1 \times 12}$

$i \times \sqrt{12}$

$i \times \sqrt{4(3)}$

$2i \sqrt{3}$

<h2> $9. \: \sqrt{ - 125}$ </h2>

$\sqrt{ - 1} \times \sqrt{125}$

$i \times \sqrt{ {5}^{2} \times 5 }$

$5i \sqrt{5}$

<h2> $10. \: \sqrt{ - 180}$ </h2>

$\sqrt{ - 1} \times \sqrt{180}$

$i \times \sqrt{ {6}^{2} \times 5 }$

$6i \sqrt{5}$

<h3>Hope it is helpful...</h3>

5 0

3 years ago

Help me out please!!!!

KonstantinChe [14]

Answer:

c)

Step-by-step explanation:

$- \frac{7}{ - f} \: is \: equal \: to \: \frac{7}{f}$

$so \: the \: answer \: is \: none \: of \: the \: above$

7 0

3 years ago

Read 2 more answers

Edg vector operations, any help appreciated!

viktelen [127]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: Add \:\: -6 \hat i - 6\hat j \:\:with \:\; Vector \:\; c$

____________________________________

$\large \tt Solution \: :$

Vector d can be represented as :

$\qquad \tt \rightarrow \: - 2 \hat i - 2 \hat j$

Vector c can be represented as :

$\qquad \tt \rightarrow \: 4 \hat i + 4\hat j$

we have to create vector d from vector c

So, let's assume a vector x, such that sum of vector x and vector c equals to vector d

$\qquad \tt \rightarrow \: x + ( 4 \hat i + 4 \hat j) = - 2 \hat i - 2 \hat j$

$\qquad \tt \rightarrow \: x = - ( 4 \hat i + 4 \hat j) - 2 \hat i - 2 \hat j$

$\qquad \tt \rightarrow \: x = (- 4 \hat i - 2 \hat i) + ( - 4 \hat j - 2 \hat j)$

$\qquad \tt \rightarrow \: x = - 6 \hat i -6 \hat j$

Henceforth, in order to get vector d, we need to add (-6i - 6j) in vector c

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0

2 years ago