Answer:
The beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz
Explanation:
Given;
velocity of wave on the string with lower tension, v₁ = 35.2 m/s
the fundamental frequency of the string, F₁ = 258 Hz
<u>velocity of wave on the string with greater tension;</u>

where;
v₁ is the velocity of wave on the string with lower tension
T₁ is tension on the string
μ is mass per unit length

Where;
T₁ lower tension
T₂ greater tension
v₁ velocity of wave in string with lower tension
v₂ velocity of wave in string with greater tension
From the given question;
T₂ = 1.1 T₁

<u>Fundamental frequency of wave on the string with greater tension;</u>
<u />
<u />
Beat frequency = F₂ - F₁
= 270.6 - 258
= 12.6 Hz
Therefore, the beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz
Answer: 40.84 m
Explanation:
Given
Radius of the disk, r = 2m
Velocity of the disk, v = 7 rad/s
Acceleration of the disk, α = 0.3 rad/s²
Here, we use the formula for kinematics of rotational motion to solve
2α(θ - θ•) = ω² - ω•²
Where,
ω• = 0
ω = v/r = 7/2
ω = 3.5 rad/s
2 * 0.3(θ - θ•) = 3.5² - 0
0.6(θ - θ•) = 12.25
(θ - θ•) = 12.25 / 0.6
(θ - θ•) = 20.42 rad
Since we have both the angle and it's radius, we can calculate the arc length
s = rθ = 2 * 20.42
s = 40.84 m
Thus, the needed distance is 40.84 m
Frequency = velocity/wavelength
Frequency = 10/20
Frequency = 0.5 Hz
Answer:
The acceleration expressed in the new units is 
Explanation:
To convert from
to
it is necessary to remember that there are 1000 meters in 1 kilometer and 3600 seconds in 1 hour:
Then by means of a rule of three it is get:


Hence, the units of meters and seconds will cancel. Notice the importance of square the ratio 3600s/1h, so that way they can match with the other units:

So the acceleration expressed in the new units is
.
Answer:
Wavelength,
Explanation:
The energy of the electron in a hydrogen atom can be calculated from the Bohr formula as :
.............(1)
Where
R is the Rydberg constant
n is the number of orbit
We need to find the wavelength of the line in the absorption line spectrum of hydrogen caused by the transition of the electron from an orbital with to an orbital with n₁ = 2 to an orbital with n₂ = 3.
Equation (1) can be re framed as :



or

So, the the wavelength of the line in the absorption line spectrum is 657 nm. Hence, this is the required solution.