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luda_lava [24]
4 years ago
6

How does the gravity in the space shuttle compare with the gravity on earth’s surface?

Physics
2 answers:
Zolol [24]4 years ago
7 0

These days they are exactly identical. All the space shuttles are currently in museums located on the surface of the Earth.

Years ago when the space shuttles were in orbit, the gravity inside a shuttle was about 85% of the gravity on the Earth's surface.

zheka24 [161]4 years ago
5 0
The gravity in the space shuttle is approximately equal to the gravity on the surface of the earth
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Dennis_Churaev [7]
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3 years ago
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If the mass of the body is doubled what should be its speed so as to maintain the same kinetic energy ?​
soldier1979 [14.2K]

Answer:

The speed should be reduced by 1/√2 or 0.707 times

Explanation:

The relationship between the kinetic energy, mass and velocity can be represented by the following equation:

K.E = ½m.v²

In this equation, the mass is inversely proportional to the square of the velocity or speed. This means that as the mass increases, the speed reduces by × 2.

Let; initial mass = m1

Final mass = m2

Initial velocity = v1

Final velocity = v2

According to the question, if the mass of the body is doubled i.e. m2 = 2m

½m1v1² = ½m2v2²

½ × m × v1² = ½ × 2m × v2²

Multiply both sides by 2

(½ × m × v1²)2 = (½ × 2m × v2²)2

m × v1² = 2m × v2²

Divide both sides by m

v1² = 2v2²

Divide both sides by 2

v1²/2= v2²

Square root both sides

√v1²/2= √v2²

v1/√2 = v2

v2 = 1/√2 v1

This shows that to maintain the same kinetic energy if the mass is doubled, the speed should be reduced by 1/√2 or 0.707 times.

8 0
3 years ago
While on Mars, two astronauts repeat the pendulum experiment you conducted earlier this term in your physics lab. They go off sc
Levart [38]

Answer:

The constant 0.091 in the astronauts' equation of the best fit line is equal to   \frac{L}{T^2}

The value of  g on Mars is  g = 3.593 \  m/s^2

Explanation:

From the question we are told that

     The line of best fit is defined by the equation  y  = 0.091 x \ and \  R^2 =  1

Now the equation of a straight line is defined as

       y = mx + c

Now comparing the given equation to this we have that

        m =  slope =  0.091

Now from the graph the formula for the slope is  

          m = \frac{L}{T^2}

=>      0.091 =  \frac{L}{T^2}

Now from the question we are told that

        T =  2 \pi \sqrt{\frac{L}{g} }

=>     \frac{g}{4\pi r^2}  =  \frac{L}{T^2} = 0.091

=>     g =  4\pi^2 * 0.091

=>      g = 3.593 \  m/s^2

                                                               

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"a needle can be made to "float" on the surface tension of water. what causes this surface tension to form"
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How do you know whether to put a nine or a 10 in front of the number on the weather station
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Good luck :)
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