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luda_lava [24]
4 years ago
6

How does the gravity in the space shuttle compare with the gravity on earth’s surface?

Physics
2 answers:
Zolol [24]4 years ago
7 0

These days they are exactly identical. All the space shuttles are currently in museums located on the surface of the Earth.

Years ago when the space shuttles were in orbit, the gravity inside a shuttle was about 85% of the gravity on the Earth's surface.

zheka24 [161]4 years ago
5 0
The gravity in the space shuttle is approximately equal to the gravity on the surface of the earth
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A leaky 10-kg bucket is lifted from the ground to a height of 16 m at a constant speed with a rope that weighs 0.7 kg/m. initial
IrinaVladis [17]

\displaystyle W =\lim_{n\to\infty}{\sum_{i=0}^{n}{(678.16 - 36.26\;x_i)\cdot\dfrac{16}{n}}}.

<h3>Explanation</h3>

The mass comes in three parts:

  • the mass of the rope,
  • the mass of the water in the leaky bucket, and
  • the mass of the bucket.

Both the mass of the rope m_\text{rope} and the mass of the water in the bucket m_\text{water} varies with the height x of the bucket. Express the two masses as a function of x:

  • m_\text{rope} = 0.7\;(16 - x),

The water in the bucket behaves like yet another rope of density 48 \;\text{kg}/ 16 \;\text{m}= 3.0\;\text{kg}\cdot\text{m}^{-1}. The mass of the water left in the bucket at height x will be

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The mass of the bucket is 10\;\text{kg}. Combining the three:

  • m(x)  = m_\text{rope}(x) + m_\text{water}(x) + m_\text{bucket} \\\phantom{m(x)} = 0.7\;(16-x) + 3.0\;(16 - x) + 10\\\phantom{m(x)} = 69.2 - 3.7\;x.

Weight of the bucket at height x:

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The bucket moves upward at a constant speed. As a result,

  • F(x) = W(x) = 678.16 - 36.26\;x.

Express the work required as a definite integral:

  • \displaystyle W = \int_{0}^{16}{F(x) \cdot dx} = \int_{0}^{16}{(678.16 - 36.26\;x)\cdot dx}.

Rewrite the definite integral as a Riemann Sum:

  • \displaystyle W = \int_{0}^{16}{(678.16 - 36.26\;x)\cdot dx} \\\phantom{W}= \lim_{n\to\infty}{\sum_{i=0}^{n}{(678.16 - 36.26\;x_i)\cdot\frac{16-0}{n}}}\\\phantom{W} = \lim_{n\to\infty}{\sum_{i=0}^{n}{(678.16 - 36.26\;x_i)\cdot\frac{16}{n}}}.
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3 years ago
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finlep [7]

Answer:

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hope this helped!

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