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Marina86 [1]
3 years ago
8

How many electrons must be removed from each of two 5.69-kg copper spheres to make the electric force of repulsion between them

equal in magnitude to the gravitational attraction between them?

Physics
1 answer:
CaHeK987 [17]3 years ago
7 0

Answer:

n=3.056*10^{9} Electrons

Explanation:

Please see attached file

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A cup of coffee is considered a Blank Space __________.
Sauron [17]

When you brew a coffee you're creating a Solution.  

Tiny particles from coffee grounds, or solutes, are dissolved in water, the solvent.


4 0
3 years ago
1. What is the formula for the period of a pendulum and what is the main determining factor in its period?
Brut [27]

Answer:

T=2\pi \sqrt{\frac{L}{g}}

Explanation:

A simple pendulum is a system consisting of a mass attached to a string, and oscillating in a periodic motion, back and forth, along an equilibrium position.

The period of a pendulum is the time it takes for the pendulum to complete one oscillation.

The period of a pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration due to gravity

From the formula, we see that the period of a pendulum does not depend on the mass.

Therefore, the only 2 factors affecting the period of a pendulum are:

- The length of the pendulum: the longer it is, the longer the period of oscillation

- The acceleration due to gravity: the greater it is, the shorter the period of the pendulum

7 0
3 years ago
PLEASE HELP!!
irga5000 [103]
You use energy from your body and press the pedals on the bike that has chains and the chains are connected to a circular ish shape and is also connected to the wheel and it spins
8 0
2 years ago
An airtight box has a removable lid of area 1.10 10-2 m2 and negligible weight. The box is taken up a mountain where the air pre
andrezito [222]

Answer:

F=7.7\times10^2 N

Explanation:

The magnitude of force required to pull the lid off the box by air pressure.

We know that Pressure, P= Force(F)/Area(A)

Force, F= P×A

Given: A=1.10\times10^{-2} m^2

P=7\times10^{4} Pa.

Therefore, F=7\times10^{4}\times1.10\times10^{-2}.

F=7.7\times10^2 N

4 0
3 years ago
A stone of mass 0.2 kg falls with an acceleration of 10.0 m/s. How big is the force that causes this acceleration?
Kobotan [32]

Answer:

\boxed {\boxed {\sf 2 \ Newtons}}

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

F= m \times a

The mass of the stone is 0.2 kilograms and the acceleration is 10.0 meters per square second.

  • m= 0.2 kg
  • a= 10.0 m/s²

Substitute the values into the formula.

F= 0.2 \ kg * 10.0 \ m/s^2

Multiply.

F=2 \ kg*m/s^2

Convert the units.

  • 1 kilogram meter per square second (kg*m/s²) is equal to 1 Newton (N)
  • Our answer of 2 kg*m/s² is equal to 2 N

F= 2 \ N

The force is <u>2 Newtons.</u>

4 0
3 years ago
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