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Marina86 [1]
3 years ago
8

How many electrons must be removed from each of two 5.69-kg copper spheres to make the electric force of repulsion between them

equal in magnitude to the gravitational attraction between them?

Physics
1 answer:
CaHeK987 [17]3 years ago
7 0

Answer:

n=3.056*10^{9} Electrons

Explanation:

Please see attached file

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3 resistors of 3,4 and 12 ohm are there. How would you connect so as to get a resistance more than 5 oh, but less than 7 ohm sho
DochEvi [55]

Answer:

<em>Connecting the 4-ohm and 12-ohm in parallel and followed by the 3-ohm resistor in series. A scheme of the configuration is attached below. Please see the file attached below to know the diagram.</em>

Explanation:

There is the following solution that satisfies all requirements indicated on statement:

<em>Connecting the 4-ohm and 12-ohm in parallel and followed by the 3-ohm resistor in series. A scheme of the configuration is attached below.</em>

R = \frac{(12\,\Omega)\cdot (4\,\Omega)}{12\,\Omega+4\,\Omega}+3\,\Omega

R = 6\,\Omega

Which observes all design requirements.

4 0
3 years ago
How do inertia and centripetal force combine to keep an object moving in circular motion?
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7 0
3 years ago
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What is 1 and 2 I need it asap
ExtremeBDS [4]
The correct answer for the first one is A) Breaking rocks into smaller pieces. The correct answer to the second one is A) It has more energy. Hope this helps.
5 0
3 years ago
HELP ME! PLEASE! SOMEONE! THIS QUESTION IS VERY HARD! THERE ARE 3 ANSWERS! HELP ME PLEASE! MAKE SURE TO EXPALIN
blondinia [14]

Answer:

search up the kinetic energy and potential energy etc. then take them and look at the characteristica are they the same? What makes them similar? Why are they different ? How? Then add the chemical nuclear and electrical changes it creates. Now the rest! There you’ve got this! If you need support I’m here! Hope this helped!

Explanation:

6 0
3 years ago
A 5cm tall object is placed 4cm in front of a converging lens that has a focal length of 8cm. Where is the image located in ____
OverLord2011 [107]

Answer:

a. -8 cm

Explanation:

d_{o} = distance of the object = 4 cm

d_{i} = distance of the image = ?

f = focal length of the converging lens  = 8 cm

using the lens equation

\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}

\frac{1}{4} + \frac{1}{d_{i}} = \frac{1}{8}

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4 0
3 years ago
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