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Y_Kistochka [10]
3 years ago
14

During lightning strikes from a cloud to the ground, currents as ... currents as high as 2.50×10^4 amps can occur and last for a

bout 40.0 microseconds . how much charge is transferred from the cloud to the earth during such a strike?
Physics
1 answer:
scZoUnD [109]3 years ago
7 0
Hello!

The answer is 1.00 Coulomb

Thank you!!!
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What electrons are in “motion”, what do you have?
Sergeeva-Olga [200]

Answer:

When a positive charged object is placed near a conductor electrons are attracted the the object. ... When electric voltage is applied, an electric field within the metal triggers the movement of the electrons, making them shift from one end to another end of the conductor. Electrons will move toward the positive side. As you know, electrons are always moving. They spin very quickly around the nucleus of an atom. As the electrons zip around, they can move in any direction, as long as they stay in their shell.

7 0
3 years ago
Assume that the amplifiers on the stage operate at a combined power of 5,000 Watts, and that 80% of this is converted to sound.
rusak2 [61]

Answer:

0.04

Explanation:

Fraction of power converted to sound = 80% = 0.08

Fraction incident upon each eardrum onstage = 0.08/2 = 0.04

6 0
3 years ago
A partical of an atom that carries a negative charge is called a a/n
jeka57 [31]
It is called a negative nuetron/atom
7 0
3 years ago
Read 2 more answers
A steel ball bearing with a radius of 1.5 cm forms an image of an object that has been placed 1.1 cm away from the bearing’s sur
Nonamiya [84]

Answer:

Check the explanation

Explanation:

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

The image is virtual

The image is upright

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

Kindly check the diagram in the attached image below.

5 0
3 years ago
How fast was the storm that hit Galveston and how men died?​
vodomira [7]

Answer:

The storm was a category 4 hurricane that struck Galveston, Texas, on September 8, 1900, bringing winds of 130 miles (210 km) per hour and high tides that overwhelmed the low-lying coastal city, demolishing buildings and claiming more than 8,000 lives.

00p- now I can actually answer :)

Hope that I helped you a little :0

3 0
3 years ago
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