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Y_Kistochka [10]
4 years ago
14

During lightning strikes from a cloud to the ground, currents as ... currents as high as 2.50×10^4 amps can occur and last for a

bout 40.0 microseconds . how much charge is transferred from the cloud to the earth during such a strike?
Physics
1 answer:
scZoUnD [109]4 years ago
7 0
Hello!

The answer is 1.00 Coulomb

Thank you!!!
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A typical laboratory centrifuge rotates at 4000 rpm. Test tubes have to be placed into a centrifuge very carefully because of th
cestrela7 [59]

Answer:

1. a_{rad}=17545.2\frac{m}{s^{2}}

2. a=4429.45 \frac{m}{s^{2}}

Explanation:

Radial acceleration is:

a_{rad}=\frac{v^2}{r} (1)

With r the radius respects the axis of rotation and v the tangential velocity that is related with angular velocity (ω) by:

v= \omega r (2)

By (2) on (1):

a_{rad}= \frac{(\omega r)^2}{r}= (\omega )^2r=(418,88\frac{rad}{s})^2(0.1m)

a_{rad}=17545.2\frac{m}{s^{2}}

To find the acceleration of the tube with the fall, we can use the expression:

\overrightarrow{J}=\overrightarrow{F}_{avg}(\varDelta t) (3)

Due impulse-momentum theorem:

\overrightarrow{J}=\overrightarrow{p}_{f}-\overrightarrow{p}_{i} (4)

with p the momentum and J the impulse. By (4) on (3):

\overrightarrow{p}_{f}-\overrightarrow{p}_{i}=\overrightarrow{F}_{avg}(\varDelta t)

And using Newton's second law (F=ma) and that (P=mv):

mv_f-mv_i=(ma)(\varDelta t) (5)

Final velocity is the velocity just after the encounter with hard floor, and initial momentum us just before that moment so the first one is zero and the second one can be found sing conservation of energy:

\frac{mv_i}{2}=mgh

v_i=\sqrt{2gh}=\sqrt{2(9.81)(1.0)}=4.43\frac{m}{s}

So (5) is:

-m(4.43)=(ma)(\varDelta t)

solving for a:

a=\frac{4.43}{\varDelta t}=\frac{4.43}{1.0\times10^{-3}}=-4429.45

It’s negative because is opposed to the tube movement.

5 0
3 years ago
A singly charged positive ion has a mass of 3.46 × 10−26 kg. After being accelerated through a potential difference of 215 V the
jasenka [17]

Answer:

1.8 cm

Explanation:

m = mass of the singly charged positive ion = 3.46 x 10⁻²⁶ kg

q = charge on the singly charged positive ion = 1.6 x 10⁻¹⁹ C

\Delta V =Potential difference through which the ion is accelerated = 215 V

v = Speed of the ion

Using conservation of energy

Kinetic energy gained by ion = Electric potential energy lost

(0.5) m v^{2} = q \Delta V\\(0.5) (3.46\times10^{-26}) v^{2} = (1.6\times10^{-19}) (215)\\(1.73\times10^{-26}) v^{2} = 344\times10^{-19}\\v = 4.5\times10^{4} ms^{-1}

r = Radius of the path followed by ion

B = Magnitude of magnetic field = 0.522 T

the magnetic force on the ion provides the necessary centripetal force, hence

qvB = \frac{mv^{2} }{r} \\qB = \frac{mv}{r}\\r =\frac{mv}{qB}\\r =\frac{(3.46\times10^{-26})(4.5\times10^{4})}{(1.6\times10^{-19})(0.522)}\\r = 0.018 m \\r = 1.8 cm

5 0
3 years ago
Where do incident rays that are parallel to the principal axis converge to after reflecting off a concave mirror?
morpeh [17]

Answer:

At focus

Explanation:

A concave mirror is converging in nature. In a mirror, concave in nature, the rays which are parallel to the principal axis are supposed to be coming from very large distances or we assume the source to be placed at infinity for such rays which are parallel to the principal axis.

These rays,  parallel to the principal axis, coming from infinity, converges at the focus of the mirror concave in nature after reflecting from the concave mirror

3 0
3 years ago
A girl police light on level ground with a force of 45 N at a 30° angle above the horizontal the girl pulls a sled 7.3 m how muc
Naya [18.7K]

Explanation:

W=Fdcos0

=45×7.3cos30

=284.4J

7 0
3 years ago
What happens if the breakdown voltage is exceeded.
s2008m [1.1K]

Answer:

this may help

Explanation:

maybe it will cause the eletric cause a fire that will mean it will spread till the fire men should come

7 0
3 years ago
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