The time for the police car to catch up with the speeding motorist is 7.6 seconds.
<h3>What time will the police car catch up with the speeding motorist?</h3>
The police car and the motorist will cover equal distances.
Let the distance covered be d.
Distance covered by the motorist = speed * time
time = t, speed = 30 m/s
d = 30t
Distance covered by the police car = acceleration * (time)
time = t - 2, acceleration = 5.0 m/s²
d = 5(t-2)²
d = 5(t² - 4t + 4)
d = 5t² - 20t + 20
Equating the two equations for distance
5t² - 20t + 20 = 30t
5t² - 50t + 20 = 0
Solving for t using the quadratic formula:
t = 9.6 second or 0.4 seconds
Since t > 2, t = 9.6 seconds
t - 2 = 9.6 - 2
t - 2 = 7.6 seconds
Therefore, the time for the police car to catch up with the speeding motorist is 7.6 seconds.
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Answer:
The velocity of the proton is 
Explanation:
The momentum of a particle is defined as the product of its mass by its velocity and we can calculate it using the following formula:
p=m*v Equation (1)
Where:
p: Is the momentum in kg*m/s
m: Is mass of the particle in kg
v: Is the velocity of the particle in m/s
Data known:
m= 1,6726 × 10^–27 kg : mass of the proton
p= 4.96 X 10^-19 kg.m/s.
We replace this data in the Equation (1):
Answer: The velocity of the proton is
