Answer:
98.4 kPa
Explanation:
Step 1: Given and required data
- Partial pressure of water vapor at 60°C (pH₂O): 19.9 kPa (this info is tabulated)
- Partial pressure of nitrogen (pN₂): 53.0 kPa
- Partial pressure of helium (pHe): 25.5 kPa
Step 2: Calculate the total pressure of the gaseous mixture
The total pressure of the gaseous mixture (P) os equal to the sum of the partial pressures of the gases that form it.
P = pH₂O + pN₂ + pHe
P = 19.9 kPa + 53.0 kPa + 25.5 kPa = 98.4 kPa
Answer:
1.) 28.0 grams of oxygen28 grams (1 mole/16 grams per mole)=1.75 moles oxygen2.)5.0 moles of Iron5 moles(55.845 grams/1 mole)=279.225 grams Iron3.) 452 grams Argon452 grams(1 mole/39.948 grams)=11.315 moles Argon4.) 16.5 moles Hydrogen16.5 moles(1.01 grams/1 mole)=16.665 grams Hydrogen
Explanation:
Answer:
14 solubility in 200 gram of water at 20 c
Explanation:
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Given molecule Lithium iodide (LiI)
Heat of hydration = -793 kj/mol
Lattice energy = -730 kJ/mol
Heat of hydration = Heat of solution - Lattice energy
Heat of solution = Hydration + Lattice = -793 + (- 730) = -1523 kJ/mol
Now,
Mass of LiI = 15.0 g
molar mass of LiI = 134 g/mol
# moles of LiI = 15/134 = 0.112 moles
Heat of solution for 1 mole of LiI = -1523 KJ
Therefore, for 0.112 moles of LiI the corresponding heat is
= 0.112 *(-1532) = 171.6 kJ