Answer: The percent yield of lithium chloride if a reaction starts with 20.0 g lithium hydroxide and yields 6.00 g lithium chloride is 17.2 %
Explanation:
The balanced chemical reaction is
To calculate the moles, we use the equation:
a) moles of
b) moles of
According to stoichiometry :
1 mole of produces = 1 mole of
Thus 0.83 moles of produce= of
Mass of
The theoretical yield of = 34.9 g
The experimental yield of ethanol = 6.00 g
Now we have to calculate the percent yield of ethanol.
Therefore, the percent yield is, 17.2 %
just say this: the green color is from the mold
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I have had this question on a test before!! Hope this helps
The balanced equation for the reaction is
C₃H₈ + 5O₂ → 3CO₂ + 4H₂<span>O
Moles (mol) = mass (g) / molar mass (g/mol)
Mass of the </span>C₃H₈ = 0.025 g
Molar mass of C₃H₈ = <span>44.1 g/mol
Hence, moles of </span>C₃H₈ = 0.025 g / 44.1 g/mol = 5.67 x 10⁻⁴ mol
The stoichiometric ratio between C₃H₈ and O₂ is 1 : 5.
Hence, moles of O₂ = moles of C₃H₈ x 5
= 5.67 x 10⁻⁴ mol x 5
= 2.835 x 10⁻³ mol
Molar mass of O₂ = <span>32.00 g/mol
Hence, mass of O</span>₂ = moles x molar mass
= 2.835 x 10⁻³ mol x 32.00 g/mol
= 0.09072 g
Hence, needed O₂ for the reaction is 0.09072 g.
Answer:
273 K
Explanation:
The temperature of a gas at STP is 273 K. This is equal to 0°C or 32°F.