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romanna [79]
3 years ago
15

what is the number of atoms of various elements present in the following compound. 2Na2SO4,2PbO,(NH4)2SO4,4KMO4,2NH4CI,3AI2(SO4)

3,Ca(HCO3)2,NH4NO2​
Chemistry
1 answer:
Ray Of Light [21]3 years ago
8 0

Answer:

Detail is given below.

Explanation:

2Na₂SO₄

There are two sodium, one sulfur and four oxygen atoms are present in Na₂SO₄.

In 2 mole of Na₂SO₄ = four sodium, two sulfur and 8 oxygen atoms are present.

2PbO

There are one oxygen and one lead atoms are present in PbO.

In 2 mole of PbO = 2 lead and 2 oxygen atoms

(NH₄)₂SO₄

There are two nitrogen, eight hydrogen, one sulfur and four oxygen atoms are present in (NH₄)₂SO₄.

4KMnO₄

There are one potassium, one manganese and four oxygen atoms are present in KMnO₄.

In 4 mole of KMnO₄ = four  potassium, four manganese and sixteen oxygen atoms

2NH₄Cl

There are one nitrogen, four hydrogen and one chlorine atoms are present in NH₄Cl.

In 2 mole of NH₄Cl = two nitrogen, eight hydrogen and two chlorine atoms

3Al₂(SO₄)₃

There are two aluminum, three sulfur and twelve oxygen atoms are present in Al₂(SO₄)₃.

In 3 mole of Al₂(SO₄)₃ = six aluminum, nine sulfur and thirty six oxygen atoms are present.

Ca(HCO₃)₂

There are one calcium, two hydrogen, two carbon and six oxygen atoms are present.

NH₄NO₂

There are two nitrogen, four hydrogen and two oxygen atoms are present in NH₄NO₂.

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Carbon-13 is an isotope. It has 6 protons and _____. 13 neutrons 7 neutrons 7 electrons 13 electrons
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You unknowingly run over a small nail while driving and it punctures your tire. When you are getting in your car the next mornin
Norma-Jean [14]

The nails can puncture the tires of the vehicles making them deflated after a while. The process of tire deflation due to a puncture is due to the process called an effusion. Thus, option c is correct.

<h3>What is effusion?</h3>

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When a tire is punctured then the gas from the tire starts to move out through the hole through effusion. This leads to deflation of the tire after some time as all the gas present inside had moved out completely.

Therefore, option c. a punctured tire deflates due to effusion.

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What is the major underlying principle of chromatography?.
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The CRC Handbook, a large reference book of chemical and physical data, lists two isotopes of indium (). The atomic mass of 4.28
ivanzaharov [21]

<u>Answer:</u> The mass of second isotope of indium is 114.904 amu

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

  .....(1)

Let the mass of isotope 2 of indium be 'x'

  • <u>For isotope 1:</u>

Mass of isotope 1 = 112.904 amu

Percentage abundance of isotope 1 = 4.28 %

Fractional abundance of isotope 1 = 0.0428

  • <u>For isotope 2:</u>

Mass of isotope 2 = x amu

Percentage abundance of isotope 2 = [100 - 4.28] = 95.72 %

Fractional abundance of isotope 2 = 0.9572

Average atomic mass of indium = 114.818 amu

Putting values in equation 1, we get:

114.818=[(112.904\times 0.0428)+(x\times 0.9572)]\\\\x=114.904amu

Hence, the mass of second isotope of indium is 114.904 amu

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3 years ago
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