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Brut [27]
2 years ago
8

You unknowingly run over a small nail while driving and it punctures your tire. When you are getting in your car the next mornin

g, you notice your tire is very deflated.
This best exemplifies which of the following processes?



diffusion



mean free path



effusion



kinetic molecular theory
Chemistry
1 answer:
Norma-Jean [14]2 years ago
7 0

The nails can puncture the tires of the vehicles making them deflated after a while. The process of tire deflation due to a puncture is due to the process called an effusion. Thus, option c is correct.

<h3>What is effusion?</h3>

Effusion is the process that defines the escape of the fluids or gases from a system through an outlet with a small diameter compared to the mean free path of the molecules.

When a tire is punctured then the gas from the tire starts to move out through the hole through effusion. This leads to deflation of the tire after some time as all the gas present inside had moved out completely.

Therefore, option c. a punctured tire deflates due to effusion.

Learn more about effusion here:

brainly.com/question/2823560

#SPJ1

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What is the molarity of a solution of Cu2SO4 if 250.0 mL of solution contains 14.1 g of Cu2SO4?
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Cu₂SO₄ = Cu + CuSO₄
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A piece of unknown metal weighs 348g. When the metal piece absorbs 6.64kj of heat , its temperature increases from 24.4C to 43.6
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Answer:

This metal could be the aluminium with a specific heat of H = 993 \frac{J}{kgC}

Explanation:

A pie of unknown metal presents a mass (M) of 348 g. This metal is heated using energy (E) of 6.64 kJ and the temperature increases from T1 =24.4 to T2 =43.6°C. We can calculate the specific heat (H) of this metal as follows

H = \frac{E}{M*(T2-T1)}

We can replace previously presented data in this equation. After simplifying and converting to adequated units, we found that

H = \frac{6640 J}{0.348 Kg*(43.6-24.4) C} =\frac{6640 J}{6.686 KgC}

Finally, the specific heat of this metal is

H = 993 \frac{J}{kgC}

The aluminium could be the metal, its specific heat is similar to that found in this problem.

Finally,  we can conclude that this metal could be the aluminium with a specific heat of H = 993 \frac{J}{kgC}

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