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Brut [27]
2 years ago
8

You unknowingly run over a small nail while driving and it punctures your tire. When you are getting in your car the next mornin

g, you notice your tire is very deflated.
This best exemplifies which of the following processes?



diffusion



mean free path



effusion



kinetic molecular theory
Chemistry
1 answer:
Norma-Jean [14]2 years ago
7 0

The nails can puncture the tires of the vehicles making them deflated after a while. The process of tire deflation due to a puncture is due to the process called an effusion. Thus, option c is correct.

<h3>What is effusion?</h3>

Effusion is the process that defines the escape of the fluids or gases from a system through an outlet with a small diameter compared to the mean free path of the molecules.

When a tire is punctured then the gas from the tire starts to move out through the hole through effusion. This leads to deflation of the tire after some time as all the gas present inside had moved out completely.

Therefore, option c. a punctured tire deflates due to effusion.

Learn more about effusion here:

brainly.com/question/2823560

#SPJ1

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A sample of 211 g of iron (III) bromide is reacted with
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FeBr₃ ⇒ limiting reactant

mol NaBr = 1.428

<h3>Further explanation</h3>

Reaction

2FeBr₃ + 3Na₂S → Fe₂S₃ + 6NaBr

Limiting reactant⇒ smaller ratio (mol divide by coefficient reaction)

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211 g of Iron (III) bromide(MW=295,56 g/mol), so mol FeBr₃ :

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\tt n=\dfrac{186}{78.0452}=2.38

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So  FeBr₃ as a limiting reactant(smaller ratio)

mol NaBr based on limiting reactant (FeBr₃) :

\tt \dfrac{6}{3}\times 0.714=1.428

6 0
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