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Brut [27]
2 years ago
8

You unknowingly run over a small nail while driving and it punctures your tire. When you are getting in your car the next mornin

g, you notice your tire is very deflated.
This best exemplifies which of the following processes?



diffusion



mean free path



effusion



kinetic molecular theory
Chemistry
1 answer:
Norma-Jean [14]2 years ago
7 0

The nails can puncture the tires of the vehicles making them deflated after a while. The process of tire deflation due to a puncture is due to the process called an effusion. Thus, option c is correct.

<h3>What is effusion?</h3>

Effusion is the process that defines the escape of the fluids or gases from a system through an outlet with a small diameter compared to the mean free path of the molecules.

When a tire is punctured then the gas from the tire starts to move out through the hole through effusion. This leads to deflation of the tire after some time as all the gas present inside had moved out completely.

Therefore, option c. a punctured tire deflates due to effusion.

Learn more about effusion here:

brainly.com/question/2823560

#SPJ1

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erastovalidia [21]

Answer:

The time taken for the cross mark to disappear decreases steadily down the column.

Explanation:

Now if we look at the data provided, we will discover that the volume of the HCl was held constant while the volume of the thiosulphate was increased steadily and the volume of water decreased steadily.

Recall that a system is more concentrated when it contains less volume of water and more volume of reactants. Hence as the volume of water in the system is being reduced, the concentration of reactants is increased.

It has been established that an increase in the concentration of reactants lead to an increase in the rate of reaction. The disappearance of the cross shows the completion of the reaction between HCl and thiosulphate. The faster or slower the cross disappears, the faster or slower the rate of reaction.

Since increase in concentration of reactants increases the rate of reaction, it is observed that as the volume of the thiosulphate increases (reactant concentration increases) the cross disappears faster (rate of reactant increases). Hence as the volume of thiosulphate increases, it takes a shorter time for the cross to disappear. This implies that the time column in the table (refer to the question) will decrease steadily as the volume of thiosulphate increases.

5 0
3 years ago
At 393 K, the pressure of a sample of nitrogen is 1.07 atm. What will the pressure be at 478 K, assuming constant volume?
True [87]

Answer:

About 1.301 atm

Explanation:

The formula that you should is PV=nRT, where P stands for pressure, V stands for volume, n stands for the number of moles, R stands for the universal gas constant, and T stands for temperature in Kelvin. Since the volume, number of moles, and universal gas constant don't change, you don't need to worry about them.

1.07V=393nR

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P=1.301 atm. Hope this helps!

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Answer: 2NH4Br(aq)+Pb(C2H302(aq)-------------------->

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Explanation:

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the spectator ions NH4 +C2H3O2 are canceled

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<span>e = mc^2 
 
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Plug in your numbers in the appropriate units.
</span><span>m=1.02 × 10^-5

pulled from another response, hope it helps</span>
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