How many grams are there in 7.3 moles of NH3?
1 answer:
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Explanation:
The given data is as follows.
= 286 kJ =
= 286000 J
,
Hence, formula to calculate entropy change of the reaction is as follows.
=
=
= 163.5 J/K
Therefore, formula to calculate electric work energy required is as follows.
=
= 237.277 kJ
Thus, we can conclude that the electrical work required for given situation is 237.277 kJ.
2.083 Liters of 6.0 M solution sulfuric acid is required. This solved using molecular calculations and Titration.
Solution:
Moles of hydrogen gas =
Then 12.5 moles of hydrogen will be obtained from Moles of Sulfuric acid = 12.5 mol
Molarity of the sulfuric acid solution = 6.0 M = 6 mol/ l
6M =
where V is the volume needed
V = 2.083 l
<h3>What is Titration?</h3>- Titration, commonly referred to as titrimetry, is a typical quantitative chemical analysis method used in laboratories to ascertain the unidentified quantity of an analyte .
- Titration is frequently referred to as volumetric analysis because it relies heavily on volume measurements. The titrant or titrator is a reagent that is prepared as a standard solution.
- To determine concentration, a solution of the analyte or titrand reacts with a known concentration and volume of the titrant. The titration volume is the amount of titrant that has responded.
- Titrations come in a variety of forms with various protocols and objectives. Redox and acid-base titrations are the two most typical types of qualitative titrations.
To learn more about titration with the given link
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