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kirza4 [7]
3 years ago
9

A race car travels along a section of a track with a constant speed of 100 m/s. If this speed is maintained for 15 minutes, how

far does the car travel within that time? (a) 30 km (b) 60 km (c) 90 km (d) 120 km
Physics
1 answer:
liberstina [14]3 years ago
7 0
(C)90 km
100x60seconds x 15 minutes/1000metres
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In a lightning bolt, a large amount of charge flows during a time of 1.2 x 10-3 s. Assume that the bolt can be represented as a
ohaa [14]

Answer: 10.58 C has flowed during the lightning bolt

Explanation:

Given that;

Time of flow t = 1.2 × 10⁻³

perpendicular distance r = 21 m

Magnetic field B = 8.4 x 10⁻⁵ T

Now lets consider the expression for magnetic field;

B = u₀I / 2πr

the current flow is;

I = ( B × 2πr ) / u₀

so we substitute

I = ( (8.4 x 10⁻⁵) × 2 × 3.14 × 21 ) / 4π ×10⁻⁷

=  0.01107792 / 0.000001256

= 8820 A

Hence the charge flows during lightning bolt  will be;

q = It

so we substitute

q = 8820 × 1.2 × 10⁻³

q = 10.58 C

therefore 10.58 C has flowed during the lightning bolt

6 0
3 years ago
One complete expression of a waveform beginning at a certain point, progressing through the zero line to the wave’s highest (cre
elixir [45]

Answer:

wavelength.

Explanation:

One complete expression of a waveform beginning at a certain point, progressing through the zero line to the wave’s highest (crest) and lowest (trough) points, and returning to the same value as the starting point is called a is called wavelength. Its can be also defined as the distance between two successive crests or trough points in wave form.

4 0
2 years ago
A projectile is launched from ground level at an angle of 30 degrees above the horizontal. Neglect air resistance and consider t
Oduvanchick [21]

Answer:

just before landing the ground

Explanation:

Let the velocity of projection is u and the angle of projection is 30°.

Let T is the time of flight and R is the horizontal distance traveled. As there is no force acting in horizontal direction, so the horizontal velocity remains constant. Let the particle hits the ground with velocity v.

initial horizontal component of velocity, ux = u Cos 30

initial vertical component of velocity, uy = u Sin 30

Time of flight is given by

T = \frac{2u Sin\theta }{g}

Final horizontal component of velocity, vx = ux = u Cos 30

Let vy is teh final vertical component of velocity.

Use first equation of motion

vy = uy - gT

v_{y}=u_{y}- g \times \frac{2u Sin\theta }{g}

v_{y}=u Sin 30 - 2u Sin 30

vy = - u Sin 30

The magnitude of final velocity is given by

v = \sqrt{v_{x}^{2}+v_{y}^{2}}

v = \sqrt{\left (uCos 30  \right )^{2}+\left (uSin 30  \right )^{2}}

v = u

Thus, the velocity is same as it just reaches the ground.

6 0
3 years ago
Which switch configuration creates a short circuit?
lara31 [8.8K]
I think the answer would be Switch 1 open; switches 2, 3, and 4 closed. It is letter D. This will happen when there is a low resistance and a high circuit so from the choices above, when two bulbs are open and one bulb is close, so there is a low resistance and high voltage.
6 0
3 years ago
We can model the motion of a bumblebee's wing as simple harmonic motion. A bee beats its wings 250 times per second, and the win
zlopas [31]

Answer:

The amplitude of the wing tip's motion is 1.6 mm.

Explanation:

Given that,

Beat = 250 /s

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We need to calculate the amplitude of the wing tip's motion

Using the equation for the maximum velocity

v_{max}=2\pi f A

A=\dfrac{v}{2\pi f}

Where,

v = speed

f = frequency

A = amplitude

Put the value into the formula

A=\dfrac{2.5}{2\pi\times250}

A=0.00159 = 1.59\times10^{-3}\ m

A=1.6\ mm

Hence, The amplitude of the wing tip's motion is 1.6 mm.

3 0
3 years ago
Read 2 more answers
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