Ask question

Ask question

All categories

3 years ago

13

A student initially 10.0 m East of his school walks 17.5 m West. The magnitude of the student's displacement, relative to the sc

hool is _________ m? The direction of the student's displacement, relative to the school is ______?

1 answer:

Fantom [35]3 years ago

3 0

Answer:

1. 7.5 m

2. towards west side

explanation:

I hope it will help you

You might be interested in

A geosynchronous satellite orbits Earth at a distance of 42,250 km from the center of Earth and has a period of 1 day. What is t

yan [13]

Answer:

The centripetal acceleration of the satellite is $a=0.22\ m/s^2$ .

Explanation:

Given that,

The distance covered by a geosynchronous satellite, d = 42250 km

The time taken by the satellite to covered distance, t = 1 day = 24 hours

Since, 24 hours = 86400 seconds

Let v is the speed of the satellite. It is given by the total distance divided by total time taken such that :

$v=\dfrac{d}{t}$

$v=\dfrac{2\pi d}{t}$

$v=\dfrac{2\pi\times 42250 \times 10^3}{86400 }$

v = 3072.5 m/s

The centripetal acceleration of the satellite is given by :

$a=\dfrac{v^2}{d}$

$a=\dfrac{(3072.5)^2}{42250 \times 10^3}$

$a=0.22\ m/s^2$

So, the centripetal acceleration of the satellite is $a=0.22\ m/s^2$ . Hence, this is the required solution.

7 0

3 years ago

the force between a planet and a spacecraft is 1 million newtons. whst will the force be iv the spacecraft moves to halfg its or

dybincka [34]

The forces of gravity between two objects are inversely proportional to
the square of the distance between them. So reducing the distance
by 1/2 means increasing the gravitational force by 2² = 4 times.
The 1 million newtons becomes 4 million newtons.

Note that this does NOT mean the satellite's altitude above the surface.
When you're calculating gravitational forces, it's the distance between
the centers of the objects. So the question is a meaningful exercise
only if we use the distance between the satellite and the planet's center.

6 0

3 years ago

The loudness of a sound will be determined by its

adoni [48]

Answer:

By its amplitude.

Explanation:

loudness is sound intensity & intensity depends on square of amplitude. for example higher the amplitude higher the intensity which means higher the loudness.

4 0

3 years ago

When one bumper car is still and the other one hits it (both cars have the same mass) what happens?

statuscvo [17]

the first bump car will move

Explanation:

this is because as long as the other bumper car is coming with force, it mass changes and then , it is able to push the other one

5 0

3 years ago

A student pushed a 100 N bicycle over a distance of 15 m in 5 s. calculate the power generated.

Umnica [9.8K]

The catch in this one is: We don't know how much <u>force</u> the student used to push the bike.

It wasn't necessarily the 100N. That's just the weight of the bike. But you know that you can push a car, a wagon, or a bicycle hard, you can push it not so hard, you can give it a little push, you can give it a big push, you can push it strong, you can push it weak, you can push it medium. The harder you push, the more it'll accelerate, but it's completely up to you how hard you want to push. That's what's so great about wheels ! That's why they were such a great invention ! This is where I made my biggest mistake. This guy came into my store one day and said he's got this great invention, it's definitely going to take off, it'll be a winner for sure, he called it a "wheel". I looked at it, I turned it over and I looked on all sides. I thought it was too simple. I didn't know then it was elegant. I threw him out. I was so dumb. I could have invested money in that guy, today I would have probably more than a hundred dollars.

Anyway, can we figure out how much force the student used to push with ? Stay tuned:

-- The bike covered 15 meters in 5 seconds. Its average speed during the whole push was (15m/5s) = 3 meters/sec.

-- If the bike started out with no speed, and its average speed was 3 m/s, then it must have been moving at 6 m/s at the end of the push.

-- If its speed increased from zero to 6 m/s in 5 seconds, then its acceleration was (6m/s / 5 sec) = 1.2 m/s²

-- The bike's weight is 100N.

(mass) x (gravity) = 100N

Bikemass = (100N) / (9.8 m/s²)

Bikemass = 10.2 kilograms

-- F = m A

Force = (mass) x (acceleration)

Force = (10.2 kg) x (1.2 m/s²)

Force = 12.24 N

-- Work = (force) x (distance)

Work = (12.24 N) x (15 m)

Work = 183.67 Joules

-- Power = (work done) / (time to do the work)

Power = (183.67 joules) / (5 seconds)

<em>Power = 36.73 watts</em>

7 0

3 years ago