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4 years ago

which element is used as rat poison and is found in the title of the murder mystery _______ and old lace

Physics

2 answers:

defon4 years ago

6 0

Explanation :

Arsenic and old lace is used in rat poison and is found in the title of the murder mystery.

Arsenic is a poisonous element. It is a metalloid that has some properties of metals and some of the nonmetals.

As it is a toxic thing. It can attack the digestive system, nervous system and on the rat's heart. If it is consumed by rats or humans in excess amount, the rat can kill very quickly.

So, Arsenic and old lace is the element.

alisha [4.7K]4 years ago

3 0

Arsenic and old lace is the title you are looking for

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An important safety consideration with an electromagnet is to disconnect the wires when not in use because they can get ________

Rashid [163]

Answer:

Hot (A)

Explanation:

because there are electrons going through there, the friction between the metallic nuclei and electrons creates vibrations known as heat.

if you touch it the electrons will run through your body and caus damadge.

5 0

3 years ago

Three liquids are at temperatures of 4 ◦C, 24◦C, and 29◦C, respectively. Equal masses of the first two liquids are mixed, and th

Scilla [17]

Answer:

T₁₃ = 24.1°C

Explanation:

Given

m = mass of each liquids (all masses are equal)

C₁ = specific heat of the first liquid

C₂ = specific heat of the second liquid

C₃ = specific heat of the third liquid

T₁ = 4°C (temperature of the first liquid)

T₂ = 24°C (temperature of the second liquid)

T₃ = 29°C (temperature of the third liquid)

Temperature of 1+2 liquids mix: T₁₂ = 21°C

Temperature of 2+3 liquids mix: T₂₃ = 26.1°C

Temperature of 1+3 liquids mix: T₁₃ = ?

We can apply the relation ∑Q = 0

We assume the system is isolated and the process is adiabatic.

<u>Mix 1</u>:

Q₁ + Q₂ = 0

where

Q₁ = m*C₁*(T₁-T₁₂)

and

Q₂ = m*C₂*(T₂-T₁₂)

then

m*C₁*(T₁-T₁₂) + m*C₂*(T₂-T₁₂) = 0

⇒ C₁*(T₁-T₁₂) + C₂*(T₂-T₁₂) = 0

⇒ (4°C-21°C)*C₁ + (24°C-21°C)*C₂ = 0

⇒ -17°C*C₁ + 3°C*C₂ = 0

⇒ C₁ = (3/17)*C₂ = 0.176*C₂ (i)

<u>Mix 2</u>:

Q₂ + Q₃ = 0

where

Q₂ = m*C₂*(T₂-T₂₃)

and

Q₃ = m*C₃*(T₃-T₂₃)

then

m*C₂*(T₂-T₂₃) + m*C₃*(T₃-T₂₃) = 0

⇒ C₂*(T₂-T₂₃) + C₃*(T₃-T₂₃) = 0

⇒ (24°C-26.1°C)*C₂ + (29°C-26.1°C)*C₃ = 0

⇒ -2.1°C*C₂ + 2.9°C*C₃ = 0

⇒ C₃ = 0.724*C₂ (ii)

<u>Mix 3</u>:

Q₁ + Q₃ = 0

where

Q₁ = m*C₁*(T₁-T₁₃)

and

Q₃ = m*C₃*(T₃-T₁₃)

then

m*C₁*(T₁-T₁₃) + m*C₃*(T₃-T₁₃) = 0

⇒ C₁*(T₁-T₁₃) + C₃*(T₃-T₁₃) = 0

⇒ (4°C-T₁₃)*C₁ + (29°C-T₁₃)*C₃ = 0

If we use the following relations C₁ = 0.176*C₂ and C₃ = 0.724*C₂ we obtain

(4°C-T₁₃)*0.176*C₂ + (29°C-T₁₃)*0.724*C₂ = 0

⇒ (4°C-T₁₃)*0.176 + (29°C-T₁₃)*0.724 = 0

⇒ 0.706°C - 0.176*T₁₃ + 21°C - 0.724*T₁₃ = 0

⇒ 0.9*T₁₃ = 21.706°C

⇒ T₁₃ = 24.1°C

5 0

3 years ago

If you precisely measure the position of a particle, you

pochemuha

<h2>Answer: destroy all information about its speed or momentum</h2>

The Heisenberg uncertainty principle postulates that the fact that <u>each particle has a wave associated with it</u>, imposes restrictions on the ability to determine its <u>position</u> and <u>speed</u> at the same time.

In other words:

<h2>It is impossible to measure <u>simultaneously </u>(according to quantum physics), and with absolute precision, the value of the position and the momentum (linear momentum) of a particle. </h2>

So, the greater certainty is seeked in determining the position of a particle, the less is known its linear momentum and, therefore, its mass and velocity.

It should be noted that this uncertainty does not derive from the measurement instruments, but from the measurement itself. Because, even with the most precise devices, the uncertainty in the measurement continues to exist.

Thus, in general, the greater the precision in the measurement of one of these magnitudes, the greater the uncertainty in the measure of the other complementary variable.

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3 years ago

write down the following units in the ascending of their value A) mm nm cm um B) 1m 1cm 1km 1mm. convert the following units int

Reptile [31]

Answer:

A) nm, um, mm, cm

B) 1mm, 1cm, 1m, 1km

A) 3500g, B) 2500m, C) 7200 seconds

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3 years ago

As the solar nebula contracts during the formation of the solar system, it Group of answer choices forms a black hole. flattens

beks73 [17]

Answer:

Flattens out into the ecliptic plane and spins faster due to conservation of angular momentum.

Explanation:

A star is formed in a molecular cloud of gas and dust, mainly composed of hydrogen and helium. The Nebular Theory establishes, for the formation of the solar system, that the cloud starts to collapse under its own gravity when it receives a shock wave from a near event, for example, a supernova explosion. That results in the cloud breaking in small pieces, and those pieces constitute a possible future star.

Then it begins to accrete and rotate as a consequence of the angular momentum.

$L = mrv\sin \theta$ (1)

Where m is the mass, r is the radius and v is the velocity and $\theta$ is the angle between the velocity and r.

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4 years ago