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Nady [450]
3 years ago
10

An object is moving in a straight line at a constant velocity.

Chemistry
2 answers:
stiv31 [10]3 years ago
5 0

The speed is constant, and in your case the speed is the y coordinate of the graph.

So, you want to draw a graph where x grows (i.e. the time passes) and y remains constant (i.e. the speed remains constant).

A graph like this is a horizontal line, because you can never move up or down. More formally, all points of the form (x, y_0), where x changes and y_0 is constant, represent the horizontal line y=y_0

Hitman42 [59]3 years ago
3 0

Answer:

An object is moving in a straight line at a constant velocity.

On a speed-time graph, how is the line displayed?

A. negative slope

<u> B. horizontally </u>

C. positive slope

D. vertically

Explanation:

When something is constant, it means it's moving at the same speed so it must be a straight line.

You might be interested in
You have 8 moles of a gas at 250 K in a 6 L container. What is the pressure of the gas? Show your work
Bogdan [553]

Hello:

In this case, we will use the Clapeyron equation:

P = ?

n = 8 moles

T = 250 K

R = 0.082 atm.L/mol.K

V = 6 L

Therefore:

P * V = n *  R * T

P * 6 = 8 * 0.082* 250

P* 6 = 164

P = 164 / 6

P = 27.33 atm


Hope that helps!

7 0
3 years ago
Isotonic compound have high melting point. Why ? Name the ions present in CaS.
yuradex [85]

Explanation:

Because a large amount of energy is required to break the strong inter-ionic attraction.

CaS => Ca2+ & S2-

3 0
3 years ago
How are endothermic and exothermic reactions the same how are they different?
svetoff [14.1K]

Endothermic reactions and Exothermic reaction are never the same.

They are both different.

Definitions

<span><span>Endothermic:- reactions that take in energy. For example:- electrolysis, thermal decomposition and the reaction between ethanic acid and sodium carbonate.
</span><span>Exothermic:- reactions that transfer energy to the surroundings. For example:- burning, neutralisation and the reaction between water and calcium oxide.</span></span>
3 0
3 years ago
How many mL of 0.715 M HCl is required to neutralize 1.25 grams of sodium carbonate? (producing carbonic acid)
jonny [76]

Answer:

34 mL

Explanation:

We'll begin by calculating the number of mole in 1.25 g of sodium carbonate, Na₂CO₃. This can be obtained as follow:

Mass of Na₂CO₃ = 1.25 g

Molar mass of Na₂CO₃ = (23×2) + 12 + (16×3)

= 46 + 12 + 48

= 106 g/mol

Mole of Na₂CO₃ =?

Mole = mass /molar mass

Mole of Na₂CO₃ = 1.25 / 106

Mole of Na₂CO₃ = 0.012 mole

Next, we shall determine the number of mole HCl needed to react with 0.012 mole of Na₂CO₃.

The equation for the reaction is given below:

Na₂CO₃ + 2HCl —> H₂CO₃ + 2NaCl

From the balanced equation above,

1 mole of Na₂CO₃ reacted with 2 moles of HCl.

Therefore, 0.012 mole of Na₂CO₃ will react with = 0.012 × 2 = 0.024 mole of HCl.

Next, we shall determine the volume of HCl required for the reaction. This is illustrated:

Mole of HCl = 0.024 mole

Molarity of HCl = 0.715 M

Volume of HCl =?

Molarity = mole /Volume

0.715 = 0.024 / volume of HCl

Cross multiply

0.715 × volume of HCl = 0.024

Divide both side by 0.715

Volume of HCl = 0.024 / 0.715

Volume of HCl = 0.034 L

Finally, we shall convert 0.034 L to mL

This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.034 L = 0.034 L × 1000 mL / 1 L

0.034 L = 34 mL

Therefore, 34 mL of HCl is needed for the reaction.

6 0
2 years ago
A 35.6 g sample of ethanol (C2H5OH) is burned in a bomb calorimeter, according to the following reaction. If the temperature ros
Oksana_A [137]
<h3>Answer:</h3>

A) -1.24 × 10^3 kJ/Mol

<h3>Explanation:</h3>

we are given;

Mass of ethanol, m = 35.6 g

Temperature change, Δt(35.0 to 76.0°C) = 41 °C

Specific heat capacity of the calorimeter, c = 23.3 kJ/°C

Molar mass of ethanol = 46.07 g/mol

We are required to the heat change of the reaction.

  • We need to note that the reaction is an exothermic reaction since there is an increase in temperature which means heat was lost to the surroundings.

Therefore; we are going to use the following steps;

<h3>Step 1 : Moles of ethanol </h3>

We know, Moles = Mass ÷ molar mass

Thus, moles of ethanol = 35.6 g ÷ 46.07 g/mol

                                      = 0.773 moles

<h3>Step 2: Enthalpy change or heat change for the reaction.</h3>

Heat change = -mcΔt

but we are given s[pecific heat capacity in Kj/°C and we require heat change in kJ/mol

Therefore;

Heat change = -(cΔt) ÷ n ( n is the number of moles)

                      = -( 23.3 kJ/°C × 41°C) ÷0.773 mol

                    = - 1.24 × 10^3 kJ/Mol

Therefore, values of ΔH of the reaction is -1.24 × 10^3 kJ/Mol

7 0
3 years ago
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