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Nady [450]
3 years ago
10

An object is moving in a straight line at a constant velocity.

Chemistry
2 answers:
stiv31 [10]3 years ago
5 0

The speed is constant, and in your case the speed is the y coordinate of the graph.

So, you want to draw a graph where x grows (i.e. the time passes) and y remains constant (i.e. the speed remains constant).

A graph like this is a horizontal line, because you can never move up or down. More formally, all points of the form (x, y_0), where x changes and y_0 is constant, represent the horizontal line y=y_0

Hitman42 [59]3 years ago
3 0

Answer:

An object is moving in a straight line at a constant velocity.

On a speed-time graph, how is the line displayed?

A. negative slope

<u> B. horizontally </u>

C. positive slope

D. vertically

Explanation:

When something is constant, it means it's moving at the same speed so it must be a straight line.

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When 45 g of an alloy, at 25oC, are dropped into 100.0 g of water, the alloy absorbs 956 J of heat. If the final temperature of
taurus [48]

Answer:

The answer to the question is

The specific heat capacity of the alloy = 1.77 J/(g·°C)

Explanation:

To solve this, we list out the given variables thus

Mass of alloy = 45 g

Initial temperature of the alloy = 25 °C

Final temperature of the alloy = 37 °C

Heat absorbed by the alloy = 956 J

Thus we have

ΔH = m·c·(T₂ - T₁) where  ΔH = heat absorbed by the alloy = 956 J, c = specific heat capacity of the alloy and T₁ = Initial temperature of the alloy = 25 °C , T₂ = Final temperature of the alloy = 37 °C  and m = mass of the alloy = 45 g

∴ 956 J = 45 × C × (37 - 25) = 540 g·°C×c  or

c = 956 J/(540 g·°C) = 1.77 J/(g·°C)

The specific heat capacity of the alloy is 1.77 J/(g·°C)

3 0
3 years ago
Calculate the mass in grams for each of the following liquids.
WITCHER [35]
The density is calculated as mass per volume, so if we want to solve for mass, we would multiply density by volume.
For Part A: if we have a density of 0.69 g/mL, and a volume of 280 mL, multiplying these will give a mass of: (0.69 g/mL)(280 mL) = 193.2 g. Rounded to 2 significant figures, this is 190 g gasoline.
For Part B: if we have a density of 0.79 g/mL, and a volume of 190 mL, multiplying these will give a mass of: (0.79 g/mL)(190 mL) = 150.1 g. Rounded to 2 significant figures, this is equal to 150 g ethanol.
3 0
3 years ago
A chemist takes 50-gram sample of sulfur powder that has a melting point of 115.2 °C. What is the melting point of a 100-gram sa
Viktor [21]

Answer:

115.2 °C since melting point is an intensive property  

Step-by-step explanation:

The melting point of a substance does not depend on how much you have.

For example, the melting point of water is 0 °C, whether it is an ice cube from the refrigerator or in the frozen pond outside.

The freezing point of a substance is an <em>intensive property</em>.

Thus, the melting point of 100 g of sulfur is 115.2 °C because melting point in an intensive property.

7 0
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How many atoms of each element are in one molecule of 2-heptanone?​
Alex17521 [72]
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Element A has 15 protons. Determine the number of neutrons in its isotope with mass number 33.
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