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vlabodo [156]
2 years ago
12

Three parts of an atom

Chemistry
2 answers:
ehidna [41]2 years ago
5 0

Answer:

the atom can be broken down into three constituents parts – protons, neutron, and electrons.

Explanation:

Each of these parts has an associated charge, with protons carrying a positive charge, electrons having a negative charge, and neutrons possessing no net charge.

Trava [24]2 years ago
3 0

The three parts of an atom are called <em>protons</em>, <em>neutrons</em>, and<em> electrons</em>.

Protons have a positive charge in an atom. The protons determine what type of element there is an it's the atomic number.

Neutrons have no charge in an atom. They are in the core of an atom along with the protons.

Electrons orbit the nucleus/core of an atom. The atomic number is the number of your protons and it is the number of electrons too.

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When CO2 decomposes into oxygen and carbon, it gives a gram ratio of 2.67:1 O2:C. When a 32.4g of CO2 decomposes, how many grams
Rufina [12.5K]

Answer : The mass of carbon and oxygen produced is 8.83 g and 23.6 g respectively.

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

CO_2\rightarrow O_2+C

As we are given:

\text{Mass of }O_2}:\text{Mass of }C=2.67:1{

According to the law of conservation of mass,

Total mass of CO_2 = Mass of O_2 + Mass of C

Total mass of CO_2 = 2.67 + 1 = 3.67 g

Now we have to calculate the mass of O_2 and C.

\text{Mass of }O_2=\frac{\text{Given mass of }CO_2}{\text{Total mass of }CO_2}\times \text{Given mass of }O_2=\frac{32.4g}{3.67g}\times 2.67=23.6g

and,

\text{Mass of }C=\frac{\text{Given mass of }CO_2}{\text{Total mass of }CO_2}\times \text{Given mass of }C=\frac{32.4g}{3.67g}\times 1=8.83g

Therefore, the mass of carbon and oxygen produced is 8.83 g and 23.6 g respectively.

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