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Vladimir [108]
3 years ago
6

A cyclist accelerates from 0 m/s to 8 m/s in 3 seconds. What is his acceleration? Is this acceleration higher than that of a car

which accelerates from 0 to 30 m/s in 8 seconds ? Please help me ..
Chemistry
1 answer:
Firlakuza [10]3 years ago
4 0
<h3>Answer:</h3>

Acceleration of the cyclist: 2.67 m/s²

The acceleration of the cyclist is lower than that of the car.

<h3>Explanation:</h3>
  • Acceleration refers to the rate of change in velocity of a body in motion.
  • It is calculated by; dividing the change in velocity by time.
  • Acceleration = (Final velocity - Initial velocity) ÷ time

In this case;

For the cyclist;

Initial velocity = 0 m/s

Final velocity = 8 m/s

time = 3 seconds

Therefore;

Acceleration = (8 m/s - 0 m/s) ÷ 3 seconds

                     = 2.67 m/s²

For the car;

  • Initial velocity = 0 m/s
  • Final velocity = 30 m/s
  • Time = 8 seconds

Therefore;

Acceleration = ( 30 m/s - 0 m/s) ÷ 8 seconds

                     = 3.75 m/s²

The acceleration of the cyclist is lower than that of the car.

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