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Valentin [98]
3 years ago
15

Help!!!!! will give brainlist

Physics
2 answers:
Mariana [72]3 years ago
7 0

Answer:

The last one

Density=mass/volume

AlexFokin [52]3 years ago
4 0
The last one: density = mass / volume
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consider two stars, star a and star b. star a has a temperature of 4900 k , and star b has a temperature of 9900 k . how many ti
ValentinkaMS [17]

The Energy flux from Star B is 16 times of the energy flux from Star A.

We have Two stars - A and B with 4900 k and 9900 k surface temperatures.

We have to determine how many times larger is the energy flux from Star B compared to the energy flux from Star A.

<h3>State Stephen's Law?</h3>

Stephens law states that if E is the energy radiated away from the star in the form of electromagnetic radiation, T is the surface temperature of the star, and σ is a constant known as the Stephan-Boltzmann constant then-

$\frac{Energy}{Area} = \sigma\times T^{4}

Now -

Energy emitted per unit surface area of Star is called Energy flux. Let us denote it by E. Then -

$E= \sigma\times T^{4}

Now -

For Star A →

T_{A} = 4900 K

For Star B →

T_{B} = 9900 K

Therefore -

$\frac{T_{B} }{T_{A} } =\frac{9900}{4900}

\frac{T_{B} }{T_{A} }= 2.02 = 2 (Approx.)

Now -

Assume that the energy flux of Star A is E(A) and that of Star B is E(B). Then -

$\frac{E(B)}{E(A)} = \frac{\sigma\times T(B)^{4} }{\sigma \times T(A)^{2} }

E(B) = E(A) x (\frac{T(B)}{T(A)} )^{4}

E(B) = E(A) x 2^{4}

E(B) = 16 E(A)

Hence, the Energy flux from Star B is 16 times of the energy flux from Star A.

To learn more about Stars, visit the link below-

brainly.com/question/13451162

#SPJ4

4 0
2 years ago
Suppose that the period of a particular ideal mass-spring system is 5 s . What would be the period of the system if the mass wer
yan [13]

Answer: T2 = 7.07s

Explanation: The period of a loaded spring of spring constant k and mass m is given by

T= 2π √m/k

With 2π constant and k, it can be seen with little algebra that

T² is proportional to mass m

Hence (T1)²/m1 = (T2) ²/m2

Where T1 = 5, T2 =?, let m1 = m hence m2 = 2m.

By substituting, we have that

5²/m = (T2) ²/2m

25 / m = (T2) ²/2m

25 × 2m = (T2) ² × m

25 × 2 = (T2) ²

50 = (T2) ²

T2 = √50

T2 = 7.07s

5 0
4 years ago
PLEASE ANSWER
Alexxandr [17]

C.joined forces

your answer

7 0
3 years ago
Read 2 more answers
The displacement of a moving object in given interval of time is zero . Would the distance travelled by the object also be zero.
kirill [66]





Hi Pupil Here's Your answer ::




➡➡➡➡➡➡➡➡➡➡➡➡➡



No, on a circle in going from one point around circular path the displacement is zero but the distance covered is equal to the circumference of the circle.

i.e.


2\pi r


⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅




Hope this helps . . . . . . .

3 0
3 years ago
Divers found two substances on the bottom of the ocean. At room temperature, both substances are liquid. Scientists then transfe
e-lub [12.9K]

Answer:

Substance 2 is a still figure and substance 1 isn't

Explanation:

5 0
2 years ago
Read 2 more answers
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