The Energy flux from Star B is 16 times of the energy flux from Star A.
We have Two stars - A and B with 4900 k and 9900 k surface temperatures.
We have to determine how many times larger is the energy flux from Star B compared to the energy flux from Star A.
<h3>State Stephen's Law?</h3>
Stephens law states that if E is the energy radiated away from the star in the form of electromagnetic radiation, T is the surface temperature of the star, and σ is a constant known as the Stephan-Boltzmann constant then-

Now -
Energy emitted per unit surface area of Star is called Energy flux. Let us denote it by E. Then -

Now -
For Star A →
= 4900 K
For Star B →
= 9900 K
Therefore -

2.02 = 2 (Approx.)
Now -
Assume that the energy flux of Star A is E(A) and that of Star B is E(B). Then -

E(B) = E(A) x 
E(B) = E(A) x 
E(B) = 16 E(A)
Hence, the Energy flux from Star B is 16 times of the energy flux from Star A.
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Answer: T2 = 7.07s
Explanation: The period of a loaded spring of spring constant k and mass m is given by
T= 2π √m/k
With 2π constant and k, it can be seen with little algebra that
T² is proportional to mass m
Hence (T1)²/m1 = (T2) ²/m2
Where T1 = 5, T2 =?, let m1 = m hence m2 = 2m.
By substituting, we have that
5²/m = (T2) ²/2m
25 / m = (T2) ²/2m
25 × 2m = (T2) ² × m
25 × 2 = (T2) ²
50 = (T2) ²
T2 = √50
T2 = 7.07s

Hi Pupil Here's Your answer ::
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No, on a circle in going from one point around circular path the displacement is zero but the distance covered is equal to the circumference of the circle.
i.e.

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Hope this helps . . . . . . .
Answer:
Substance 2 is a still figure and substance 1 isn't
Explanation: