All categories

3 years ago

A penny is dropped from the top of a building

Physics

1 answer:

dsp733 years ago

3 0

Answer:

145 speed would it hit the ground

You might be interested in

Which two factors determine the force of gravity between two objects?

Mila [183]

Distance and inertia

5 0

3 years ago

When entering an expressway, in the acceleration lane you should: A search for a gap in traffic and adjust your speed to the spe

sattari [20]

Answer:A

Explanation: search for a gap in traffic and adjust your speed to the speed of the traffic.

3 0

3 years ago

Given that an integer variable count has already been declared and assigned a value: Write a statement that writes the value of

Natalija [7]

Answer:

cout<<count;

Explanation:

cout<<count;

The above is a C++ command will write to the standard output device (stdout).

That means that one is printing an output on the main output device for that session... whatever that may be (any output device such as monitor, printer, the user's console, a tty session, a file etc).

What that device may be varies depending on how the program is being run and from where.

The kind of statement that writes to standard output are print statement

4 0

3 years ago

Read 2 more answers

A cheetah can run at 30 m/s but only for about 12s. how far will it run in that time

Mashutka [201]

About 360 meters I hope this helps

6 0

3 years ago

Read 2 more answers

Batteries are rated in terms of ampere-hours (A·h). For example, a battery that can produce a current of 2.00 A for 3.00 h is ra

Reptile [31]

(a) 423 J

The power of the battery is the ratio between the total energy stored (E) and the time elapsed (t):

$P=\frac{E}{t}$

However, the power is also the product of the voltage (V) and the current (I):

$P=VI$

Linking the two equations together,

$\frac{E}{t}=VI\\E=VIt$

Since we know:

V = 9.0 V

$I \cdot t = 47.0 A\cdot h$

We can calculate the total energy:

$E=(9.0 V)(47 A \cdot h)=423 J$

(b) $7.79\cdot 10^{-6}$ dollars

The battery has a total energy of E = 423 J. (2)

1 Watt (W) is equal to 1 Joule (J) per second (s):

$1 W = \frac{1 J}{1 s}$

so 1 kW corresponds to 1000 J/s:

$1 kW = \frac{1000 J}{1 s}$

Multiplying both side by 1 hour (1 h):

$1 kW \cdot h = \frac{1000 J}{1 s} 1 h$

and $1 h = 3600 s$ , so

$1 kWh = \frac{1000 J}{1 s}\cdot 3600 s =3.6\cdot 10^6 J$

So we find the conversion between kWh and Joules. So now we can convert the energy from Joules (2) into kWh:

$1 kWh = 3.6\cdot 10^6 J = x : 423 J\\x=\frac{1 kWh \cdot 423 J}{3.6\cdot 10^6 J}=1.18\cdot 10^{-4}kWh$

And since the cost is $0.0660 per kilowatt-hour, the total cost will be

$C=$0.0660\cdot 1.18\cdot 10^{-4} kWh=7.79\cdot 10^{-6}$ dollars

6 0

4 years ago