Suppose that two objects attract each other with a gravitational force of 16 units. If the mass of both objects was doubled, and
1 answer:
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Answer:
3335400 N/m² or 483.75889 lb/in²
Explanation:
g = Acceleration due to gravity = 9.81 m/s²
A = Area = 1.5 cm²
m = Mass of woman = 51 kg
F = Force = mg
When we divide force by area we get pressure
The pressure exerted on the floor is 3335400 N/m² or 483.75889 lb/in²
Answer:
The velocity of the truck after this elastic collision is 15.7 m/s
Explanation:
It is given that,
Mass of the car,
Mass of the truck,
Initial velocity of the car,
Initial velocity of the truck, u₂ = 0
After the collision the velocity of the car is, v₁ = -11 m/s
Let v₂ is the velocity of the truck after this elastic collision. Using the conservation of momentum as :
So, the velocity of the truck after this elastic collision is 15.7 m/s. Hence, the correct option is (c).