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The seagull's approximate height above the ground at the time the clam was dropped is 4 m</h2>
Explanation:
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Time, t = 3 s
Substituting
s = ut + 0.5 at²
s = 0 x 3 + 0.5 x 9.81 x 3²
s = 44.145 m
The seagull's approximate height above the ground at the time the clam was dropped is 4 m
It is called air pressure
Answer: average speed of the ball would be 48 mph
Explanation:
because all you have to do is multiply 24 x .5 and that gives you your answer
Answer:
acceleration = 45 m/s²
Time = 20 seconds
Explanation:
We are given;
Distance; s = 90m
Final velocity;v = 90 m/s
Since shot from rest, initial velocity;u = 0 m/s
So, to find the acceleration, we can use Newton's 2nd law of motion which is;
v² = u² + 2as
Where a is acceleration
Plugging in the values;
90² = 0² + 2a(90)
8100 = 180a
a = 8100/180
a = 45 m/s²
Now, for the time, we will use Newton's 1st law of motion which is;
v = u + at
Where t is time;
So;
90 = 0 + 4.5t
90 = 4.5t
t = 90/4.5
t = 20 seconds
Answer:MATTER IS ANYTHING THAT HAS VOLUME AND MASS. ALL MATTER TAKES UP SPACE. THE AMOUNT OF SPACE TAKEN UP, OR OCCUPIED, BY AN OBJECT IS KNOWN AS THE OBJECT'S VOLUME. THE CURVE THAT YOU SEE AT THE LIQUID'S SURFACE HAS A SPECIAL NAME - THE MENISCUS.
Explanation:
