Answer:
2.03 x 10²⁴N
Explanation:
Given parameters:
Mass of moon = 7.34 x 10²²kg
Mass of the earth = 5.97 x 10²⁴kg
Distance = 3.8 x 10⁵km
Unknown:
Gravitational force of attraction = ?
Solution:
To find the gravitational force of attraction between the masses, we use the expression below;
F = 
G is the universal gravitation constant
m is the mass
1 and 2 represents moon and earth
r is the distance
F = 
F = 
= 2.03 x 10²⁴N
The atoms of some materials have no free electrons in their outer orbits. These electrons are busy doing other jobs, like being shared in the orbits of two adjacent atoms. They are so closely held that it is very difficult to pull them away. Most compounds of carbon and hydrogen are like this.
<span>Plastics, whose molecules are made from long combinations of carbon and hydrogen atoms, have few or no free electrons. This means that plastics are poor conductors of electricity (and they are also poor conductors of heat). hope that helped.</span>
Answer:
The atom becomes a positively charged ion.
Explanation:
- The building blocks of an atom are protons, neutrons, and electrons.
- The protons and neutrons present in the core of the atom are called nucleus.
- The electrons are scattered in an ordered way around the nucleus.
- The protons are positively charged and the electrons are negatively charged particles. The neutrons do not possess any charges.
- Binding energy is supplied to the atom to remove an electron.
- It is possible to remove the electrons of the lighter elements.
- When an electron is removed from the hydrogen atom. It becomes positively charged ion or simply proton.
- When all of the electrons are removed from the helium atom, it becomes a positively charged α particle.
- It is practically very difficult to remove all of the electrons from the heavier elements.
- When all of the electrons are removed from an atom it becomes an unstable positively charged ion.
Answer:
P = 1 x 10⁸ Pa
Explanation:
given,
radius = 2.0 ×10⁻¹⁰ m
Temperature
T = 300 K
Volume of gas molecule =
V = 33.51 x 10⁻³⁰ m³
we know,
P V = 1 . k T
k = 1.38 x 10⁻²³ J/K
P(33.51 x 10⁻³⁰) = 1 . (1.38 x 10⁻²³) x 300
P = 1.235 x 10⁸ Pa
for 1 significant figure
P = 1 x 10⁸ Pa
