(a) the weight of the fish is:
and this is the force that stretches the spring by
. So, we can use Hook's law to find the constant of the spring:
(b) The fish is pulled down by 2.8 cm = 0.028 m more, so now the total stretch of the spring is
But this is also the amplitude of the new oscillation, because this is the maximum extension the spring can get, so A=6.5 cm.
The angular frequency of oscillation is given by:
and so the frequency is given by
and this is the force that stretches the spring by
(b) The fish is pulled down by 2.8 cm = 0.028 m more, so now the total stretch of the spring is
But this is also the amplitude of the new oscillation, because this is the maximum extension the spring can get, so A=6.5 cm.
The angular frequency of oscillation is given by:
and so the frequency is given by