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Pachacha [2.7K]
2 years ago
8

True or False. Only the initial ball carrier can recover a fumble.

Physics
2 answers:
vovikov84 [41]2 years ago
8 0

Answer:

true

Explanation:

Mrrafil [7]2 years ago
4 0

Answer:

A fumbled ball may be recovered and advanced by either team

hope it helps

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An electron moving with a velocity = 5.0 × 107 m/s enters a region of space where perpendicular electric and a magnetic fields a
Cloud [144]

Answer:

magnetic field will allow the electron to go through 2 x 10^{4}  T k

Explanation:

Given data in question

velocity = 5.0 × 10^{7}

electric filed = 10^{4}

To find out

what magnetic field will allow the electron to go through, undeflected

solution

we know if electron move without deflection i.e. net force is zero on electron and we can say both electric and magnetic force equal in magnitude and opposite in directions

so we can also say

F(net) = Fe + Fb i.e. = 0

q V B +  q E = 0

q will be cancel out

10^{4}j + 5e + 7i × B =  0

B = 2 x 10^{4}  T k

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3 years ago
Jennifer is making a collage using her favorite photos. She wants to cover the collage with something that allows her to see the
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B.) A transparent material
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2 years ago
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I have a problem in this questions?
photoshop1234 [79]

Answer:

8.46E+1

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = 39 C

Charge 2 (q₂) = –53 C

Force (F) of attraction = 26×10⁸ N

Electrical constant K) = 9×10⁹ Nm²/C²

Distance apart (r) =?

The distance between the two charges can be obtained as follow:

F = Kq₁q₂ / r²

26×10⁸ = 9×10⁹ × 39 × 53 / r²

26×10⁸ = 1.8603×10¹³ / r²

Cross multiply

26×10⁸ × r² = 1.8603×10¹³

Divide both side by 26×10⁸

r² = 1.8603×10¹³ / 26×10⁸

r² = 7155

Take the square root of both side

r = √7155

r = 84.6 m

r = 8.46E+1 m

7 0
2 years ago
During the motion of the slinky in a transverse wave, what do the particles of the slinky coil do?
Mazyrski [523]

Answer:

C.) The slinky particles move up and down

Explanation:

<u>Transverse Wave</u>-

<em>A wave that has a disturbance perpendicular to the wave motion</em>

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<em>Hello! This is the correct answer! Have a blessed day! :)</em>

<em>If you are in K12, please review the lesson! :)  It will give you some very helpful definitions!  I hope this helped!</em>

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2 years ago
Visible light represents a very small portion of the electromagnetic spectrum. Radiation to the left in the image, such as micro
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X rays have a higher frequency so A
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