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Pachacha [2.7K]
3 years ago
8

True or False. Only the initial ball carrier can recover a fumble.

Physics
2 answers:
vovikov84 [41]3 years ago
8 0

Answer:

true

Explanation:

Mrrafil [7]3 years ago
4 0

Answer:

A fumbled ball may be recovered and advanced by either team

hope it helps

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Suman climb a 5 metre high ladder in 10 second calculate his power the mass of his body is 50 kg​
nadezda [96]

Answer:

245W

Explanation:

Given parameters:

Mass of his body = 50kg

Height of climb  = 5m

Time  = 10s

Unknown:

Power = ?

Solution:

Power is defined as the rate at which work is done;

 Mathematically,

           Power  = \frac{work done}{time}

  Work done  = mgh

m is the mass

g is the acceleration due to gravity

h is the height

  Work done  = 50 x 9.8 x 5  = 2450J

 

          Power  = \frac{2450}{10}   = 245W

7 0
3 years ago
How much heat is required to raise the temperature of 2.0 kg of concrete from 10C to 30C? (The specific heat of concrete is 880
Phantasy [73]

Answer:B

Explanation:

8 0
3 years ago
A potential difference of 53 mV is developed across the ends of a 12.0-cm-longwire as it moves through a 0.27 T uniform magnetic
Klio2033 [76]

Answer:

The angle between the magnetic field and the wire’s velocity is 19.08 degrees.                                            

Explanation:

Given that,

Potential difference, V = 53 mV

Length of the wire, l = 12 cm = 0.12 m

Magnetic field, B = 0.27 T

Speed of the wire, v = 5 m/s

Due to its motion, an emf is induced in the wire. It is given by :

\epsilon=Blv\sin\theta

Here,

\theta is the angle between magnetic field and the wire’s velocity

\sin\theta=\dfrac{\epsilon}{Blv}\\\\\sin\theta=\dfrac{53\times 10^{-3}}{0.27\times 0.12\times 5}\\\\\sin\theta=0.327\\\\\theta=19.08^{\circ}

So, the angle between the magnetic field and the wire’s velocity is 19.08 degrees.

8 0
3 years ago
You throw a stone vertically upward with an initial speed of 6.4 m/s from a third-story office window.
Gwar [14]
-12 = 6.2*t - 4.9*t² → t = 2.32 sec (quadratic formula) 

<span>V = Vi -g*t = 6.2 - 9.8*2.32 = -16.5 m/s</span>
5 0
3 years ago
A(n) 71.1 kg astronaut becomes separated from the shuttle, while on a space walk. She finds herself 70.2 m away from the shuttle
denpristay [2]

Answer:

10.347 minutes.

Explanation:

According to F = ma, she exerts force on camera of the magnitude

F = 0.67Kg*12m/s^{2} = 8.04N, assuming it took her one second to accelerate camera to 12m/s, then by newtons third law, which says every action has equal and opposite reaction , the camera exerts the same amount of force on the astronaut which gives her acceleration of a = \frac{8.04N}{70.2Kg} = 0.1130801680m/s^2.

and velocity of V = 0.1130801680m/s.

at this velocity , the astronaut has to cover the distance of 70.2 meters, it will take her 620.7985075s = 10.347 min to get to the shuttle (using S = vt).

4 0
3 years ago
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