Answer:
1.17 m
Explanation:
From the question,
s₁ = vt₁/2................ Equation 1
Where s₁ = distance of the reflecting object for the first echo, v = speed of the sound in air, t₁ = time to dectect the first echo.
Given: v = 343 m/s, t = 0.0115 s
Substitute into equation 1
s₁ = (343×0.0115)/2
s₁ = 1.97 m.
Similarly,
s₂ = vt₂/2.................. Equation 2
Where s₂ = distance of the reflecting object for the second echo, t₂ = Time taken to detect the second echo
Given: v = 343 m/s, t₂ = 0.0183 s
Substitute into equation 2
s₂ = (343×0.0183)/2
s₂ = 3.14 m
The distance moved by the reflecting object from s₁ to s₂ = s₂-s₁
s₂-s₁ = (3.14-1.97) m = 1.17 m
Answer:
The correct answer to the following question will be "Period".
Explanation:
The Period seems to be the time deemed necessary for such a perfect cycle of vibration to transfer a particular moment. Because as the amplitude of the wave raises, the wavelength falls.
It is denoted by "T" and its formula will be:
⇒ ![T = \frac{1}{F}](https://tex.z-dn.net/?f=T%20%20%3D%20%5Cfrac%7B1%7D%7BF%7D)
Where, T = Period
F = Frequency
The other given choices are not related to the given circumstances. So that the above would be the right answer.
Answer:
12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.
Explanation:
In the United States, a standard "drink" of beer has 12 ounces, a standard "drink" of wine has 5 ounces and standard drink of liquor has 1.5 ounces. Then, we obtain the quantity of drinks by dividing the total volume of each drink by its respective unit volume and summing each term. That is:
![N = \frac{12\,oz}{12\,\frac{oz}{dr} }+\frac{12\,oz}{5\,\frac{oz}{dr} }+\frac{3\,oz}{1.5\,\frac{oz}{dr} }](https://tex.z-dn.net/?f=N%20%3D%20%5Cfrac%7B12%5C%2Coz%7D%7B12%5C%2C%5Cfrac%7Boz%7D%7Bdr%7D%20%7D%2B%5Cfrac%7B12%5C%2Coz%7D%7B5%5C%2C%5Cfrac%7Boz%7D%7Bdr%7D%20%7D%2B%5Cfrac%7B3%5C%2Coz%7D%7B1.5%5C%2C%5Cfrac%7Boz%7D%7Bdr%7D%20%7D)
![N = 1\,dr+2.4\,dr+2\,dr](https://tex.z-dn.net/?f=N%20%3D%201%5C%2Cdr%2B2.4%5C%2Cdr%2B2%5C%2Cdr)
![N = 5.4\,dr](https://tex.z-dn.net/?f=N%20%3D%205.4%5C%2Cdr)
![N = 6\,dr](https://tex.z-dn.net/?f=N%20%3D%206%5C%2Cdr)
12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.
<span>Mass of the ball is m = 0.10kg
Initial speed of the Ball v = 15m/s
a. When the ball is at maximum height the velocity is 0
Momentum of ball = mass x velocity
Momentum = 0.10kg x 0 = 0
b. Getting the maximum height,
Using the conservation of energy equation KEinitial = mgh
1/2mVin^2 = mgh => h = v^2/2g
h = 15^2/2x9.8 = 11.48m => Half Height h = 5.96m
Applying the conservation of energy equation at halfway V^2 = 2gh
V = square root of (2x9.8x5.96) => V = square root of (116.816)
So the velocity at the half way V = 10.81 m/s
Momentum M = m x V => M = 0.10 x 10.81 => M = 1.081kg-m/s</span>