Answer:
the work done by gravity on the boy is 604.62 J
Explanation:
Given;
distance the boy slides, d = 3 m
angle of inclination of the playground, θ = 40⁰
mass of the boy, m = 32 kg
The vertical height, h, above the ground through which the boy falls represents the height of the triangle which is the opposite side.
The distance through which the boy slides, d, represents the hypotenuse side of the right triangle.
The work done by gravity on the boy is calculated as;
W = P.E = mgh
= 32kg x 9.8m/s² x 1.928m
= 604.62 J
Therefore, the work done by gravity on the boy is 604.62 J
Answer:
time constant will decrease and steady state current will decrease on increasing the resistance
Explanation:
As we know that the EMF of cell is E which is used to connected across a resistor and an inductor.
So we will have
here we know that
now here we have
so if we increase the value of resistance of the wire then the time constant will decrease
and hence it will take less time to reach near the steady state value
also the steady state current will be smaller in that case
Answer: Place his feet parallel to the baseline prior to tossing the ball
Formula for distance is d=st
so for speed is s=d/t
48 km per hour
