Question

In a reaction where an OH group is substituted with a Cl, 15.02 g of 3-phenyl-2-butanol (MW=150.2 g/mol) is the starting material. What is the theoretical yield in grams of the product? (the product of the above reaction has a molecular weight of 168.1 g/mol)

Answer 1

Answer:

16.81 g of C₁₀H₁₃Cl

Explanation:

When 3-phenyl-2-butanol reacts with HCl it undergoes a substitution reaction to form 2-chloro-3-phenylbutane and water.

C₁₀H₁₄O + HCl ⇄ C₁₀H₁₃Cl + H₂O

The molar mass of 3-phenyl-2-butanol is 150.2 g/mol and the molar mass of 2-chloro-3-phenylbutane is 168.1 g/mol. The molar ratio is 1:1. Then, for 15.02 g of 3-phenyl-2-butanol, the theoretical yield is:

$15.02gC_{10}H_{14}O.\frac{168.1gC_{10}H_{13}Cl}{150.2gC_{10}H_{14}O} =16.81gC_{10}H_{13}Cl$