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kari74 [83]
4 years ago
13

In a reaction where an OH group is substituted with a Cl, 15.02 g of 3-phenyl-2-butanol (MW=150.2 g/mol) is the starting materia

l. What is the theoretical yield in grams of the product? (the product of the above reaction has a molecular weight of 168.1 g/mol)
Chemistry
1 answer:
Brrunno [24]4 years ago
8 0

Answer:

16.81 g of C₁₀H₁₃Cl

Explanation:

When 3-phenyl-2-butanol reacts with HCl it undergoes a substitution reaction to form 2-chloro-3-phenylbutane and water.

C₁₀H₁₄O + HCl ⇄ C₁₀H₁₃Cl + H₂O

The molar mass of 3-phenyl-2-butanol is 150.2 g/mol and the molar mass of 2-chloro-3-phenylbutane is 168.1 g/mol. The molar ratio is 1:1. Then, for 15.02 g of 3-phenyl-2-butanol, the theoretical yield is:

15.02gC_{10}H_{14}O.\frac{168.1gC_{10}H_{13}Cl}{150.2gC_{10}H_{14}O} =16.81gC_{10}H_{13}Cl

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If the input force applied to one end of a first-class lever is 8 N, and the fulcrum is located 6 m away from the input force bu
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4 0
3 years ago
What is the percent of oxygen by mass in a pure sample of fecr2o4? 1. 52% 2. 13% 3. 37% 4. 7.1% 5. 29%?
Marta_Voda [28]
Let us suppose that we have 1 mol of FeCr2O4. I'm going to use approximate masses because I have no idea what your periodic table will say. Just put in the exact masses from your periodic table.

Fe = 56
Cr*2 = 2*52 = 104
O4 = 4*16 = 64
===========
Total = 56 + 104 + 64 = 224
The % oxygen = (64 / 224) * 100 = 28.5 % but none of your answers match this. Perhaps you are talking about Fe2(Cr2O4)3 The brackets make all the difference in the world.

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Cr * 6 = 312
O * 12 = 192
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The % Oxygen = (192 / 616) * 100 = 31% roughly. That answer isn't there either. 

Let's wait and see who else answers.

6 0
3 years ago
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