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PIT_PIT [208]
2 years ago
6

I NEED THE ANSWER QUICKKK!!!

Chemistry
1 answer:
julsineya [31]2 years ago
7 0

Answer:  This is hard to do accurately, but here is my best assessment.

Explanation:

Experiment:  B  -  describes how the experiment was done

Conclusion:  A  -  The data support the prevailing hypothesis

Research:  D   -   This is what we analyzed

Analysis:  C  -  We compared the data

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What is the difference between a conductor and an insulator?
USPshnik [31]

Answer:materials that impede the free flow of electrons from atom to atom and molecule to molecule.

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How does increasing the temperature affect a reaction?
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Answer:A. An increase in temperature increases the reaction rate.

Explanation:because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.

4 0
3 years ago
Converting carbon to nitrogen by increasing the number of protons from 6 to 7 and decreasing the number of neutrons from 8 to 7
Anton [14]

this is beta decay as the mass number stays the same but proton number changes, this is specifically beta minus as a neuron changes into a proton
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3 years ago
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The pressure in a cylinder of nitrogen continuously decreases as a gas is released from it. On the other hand, a cylinder of pro
Juli2301 [7.4K]

Answer:

Explanation:

Nitrogen gas in nitrogen cylinder is in gaseous form only . So when gas is released , pressure decreases because moles of  gas in the cylinder decreases .

Propane gas in cylinder is in liquified form . The gas is partially in gaseous and liquid form . So when gas is released outside , pressure decreases inside but due to low pressure , some liquid form is converted into gaseous form which restores the pressure of gas inside cylinder . Hence , the pressure of gas remains unchanged inside cylinder.  

4 0
3 years ago
A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.
Lubov Fominskaja [6]

Answer:

Ag_2SO_4

Explanation:

Formula for the calculation of no. of Mol is as follows:

mol=\frac{mass\ (g)}{molecular\ mass}

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

Ag, \frac{0.05305}{0.02657} \approx 2

S, \frac{0.02657}{0.02657} \approx 1

O, \frac{0.10594}{0.02657} \approx 4

Therefore, empirical formula of the compound = Ag_2SO_4

7 0
3 years ago
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