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PIT_PIT [208]
2 years ago
6

I NEED THE ANSWER QUICKKK!!!

Chemistry
1 answer:
julsineya [31]2 years ago
7 0

Answer:  This is hard to do accurately, but here is my best assessment.

Explanation:

Experiment:  B  -  describes how the experiment was done

Conclusion:  A  -  The data support the prevailing hypothesis

Research:  D   -   This is what we analyzed

Analysis:  C  -  We compared the data

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Calculate 50g 25.0c to 95.000<br>O.897 J / (g.c)​
chubhunter [2.5K]

Answer:

Q = 3139.5 j

Explanation:

Given data:

Mass = 50 g

Initial temperature = 25°C

Final temperature = 95°C

Specific heat capacity = 0.897 j/g.°C

Heat absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT =  95°C - 25°C

ΔT = 70°C

Q = m.c. ΔT

Q = 50 g× 0.897 J/g.°C ×70°C

Q = 3139.5 j

3 0
3 years ago
Is hot tea homogeneous or heterogeneous?
OleMash [197]
<span>homogeneous  because particles are mixed uniformly</span>
6 0
3 years ago
What happens when two hydrogen atoms enter the ETS as part of either NADH or FADH2? Two hydrogen and one oxygen react to form a
gtnhenbr [62]
I think the correct answer from the choices listed above is the second option. When two hydrogen atoms enter the ETS as part of either NADH or FADH2, the two hydrogen atoms are split into two H+ and two electrons. Hope this answers the questions.
7 0
3 years ago
Read 2 more answers
The table below shows the number of sub-atomic particles in an atom of magnesium.
Fittoniya [83]

Answer:

24

Explanation:

7 0
3 years ago
After mixing an excess PbCl2 with a fixed amount of water, it is found that the equilibrium concentration of Pb2 is
Tanzania [10]

Answer:

Ksp = 8.8x10⁻⁵

Explanation:

<em>Full question is:</em>

<em>After mixing an excess PbCl2 with a fixed amount of water, it is found that the equilibrium concentration of Pb2+ is 2.8 × 10–2 M. What is Ksp for PbCl2?</em>

<em />

When an excess of PbCl₂ is added to water, Pb²⁺ and Cl⁻ ions are produced following Ksp equilibrium:

PbCl₂(s) ⇄ Pb²⁺ + 2Cl⁻

Ksp = [Pb²⁺] [Cl⁻]²

If an excess of PbCl₂ was added, an amount of Pb²⁺ is produced (X) and twice Pb²⁺ is produced as Cl⁻ (2X):

Ksp = [X] [2X]²

Ksp = 4X³

As X is the amount of Pb²⁺ = 2.8x10⁻²M:

Ksp = 4(2.8x10⁻²)³

<h3>Ksp = 8.8x10⁻⁵</h3>
4 0
3 years ago
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