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olga nikolaevna [1]
3 years ago
11

As a water molecule how would I go threw the whole water cycle???

Chemistry
2 answers:
Alik [6]3 years ago
6 0
<span>The water cycle is like a big circle and doesn’t really have a starting point. There are 4 main stages involved in water cycle i.e. evaporation, condensation, precipitation and runoff, so, I'd say you become water, you evaporate, then you turn into a cloud and rain, then runoff.</span>
kiruha [24]3 years ago
6 0
You would evaporate. then you would become rain. then you will fall to earth and start the whole process over again.
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In the 1800s, a popular belief known as vitalism stated that life processes could not be explained by the laws of physics and ch
soldi70 [24.7K]

The question is incomplete, the complete question is;

In the 1800s, a popular belief known as vitalism stated that life processes could not be explained by the laws of physics and chemistry,and were instead dictated by an independent life force. Which discovery most likely caused scientists to revise this hypothesis regarding the origin of life on Earth?

a. that inorganic compounds existed within live organisms

b. that organic compounds could be synthesized in a laboratory

c. that RNA could serve as a template to synthesize DNA

d. that self-replicating molecules existed inside cells

Answer:

b. that organic compounds could be synthesized in a laboratory

Explanation:

Vitalism is the belief that "living organisms are fundamentally different from non-living entities because they contain some non-physical element or are governed by different principles than are inanimate things"(wikipedia).

This theory held that the molecules involved in life processes could not be synthesized in the laboratory.

All these were upturned after Fredrich Whöler's synthesis of urea in 1828. He was able to show that molecules involved in life process can also be synthesized in the laboratory. This gave rise to modern synthetic organic chemistry.

6 0
3 years ago
WILL GIVE BRAINLIEST
dedylja [7]

Answer:

In order to be able to solve this problem, you will need to know the value of water's specific heat, which is listed as

c=4.18Jg∘C

Now, let's assume that you don't know the equation that allows you to plug in your values and find how much heat would be needed to heat that much water by that many degrees Celsius.

Take a look at the specific heat of water. As you know, a substance's specific heat tells you how much heat is needed in order to increase the temperature of 1 g of that substance by 1∘C.

In water's case, you need to provide 4.18 J of heat per gram of water to increase its temperature by 1∘C.

What if you wanted to increase the temperature of 1 g of water by 2∘C ?

This will account for increasing the temperature of the first gram of the sample by n∘C, of the the second gramby n∘C, of the third gram by n∘C, and so on until you reach m grams of water.

And there you have it. The equation that describes all this will thus be

q=m⋅c⋅ΔT , where

q - heat absorbed

m - the mass of the sample

c - the specific heat of the substance

ΔT - the change in temperature, defined as final temperature minus initial temperature

In your case, you will have

q=100.0g⋅4.18Jg∘C⋅(50.0−25.0)∘C

q=10,450 J

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