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butalik [34]
3 years ago
8

Last month Dr. Hruda's electric bill showed that she used 249 kW-hr. How many Joules (kJ) did Dr. Hruda use?

Physics
1 answer:
Leokris [45]3 years ago
6 0

Answer:

erwqffffff

Explanation:

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A 0.350kg bead slides on a curved fritionless wire,
LuckyWell [14K]

Answer:

h2 = 0.092m

Explanation:

From a balance of energy from point A to point B, we get speed before the collision:

m1*g*h-\frac{m1*V_B^2}{2}=0  Solving for Vb:

V_B=\sqrt{2gh}=6.56658m/s

Since the collision is elastic, we now that velocity of bead 1 after the collision is given by:

V_{B'}=V_B*\frac{m1-m2}{m1+m2} = \sqrt{2gh}* \frac{m1-m2}{m1+m2}=-1.34316m/s

Now, by doing another balance of energy from the instant after the collision, to the point where bead 1 stops, we get the distance it rises:

m1*g*h2-\frac{m1*V_{B'}^2}{2}=0 Solving for h2:

h2 = 0.092m

6 0
3 years ago
How does gravity affect the motions of Earth and the Moon?
RoseWind [281]

Answer:

The Sun's gravitational pull keeps our planet orbiting the Sun. The motion of the Moon is affected by the gravity of the Sun and Earth. Moon's gravity pulls on the Earth and makes the tides rise and fall.

8 0
3 years ago
Read 2 more answers
If the wavelength of a wave increases does its frequency also increase?
irinina [24]
Frequency decreases whilst wavelength increases and the opposite also occurs
4 0
3 years ago
You throw a rock horizontally out of a 7th story window. You time that it takes 3.7 seconds to hit the ground, and measure that
Nady [450]
Since we are only looking at the vertical height, we can use the free fall equation to find the height:
h = 0.5*g*t^2, where h is height in m, g is acceleration due to gravity (9.81 m/s^2), and t is time in seconds
h = 0.5*(9.81 m/s^2)*(3.7 s)^2
h = 67.15 m
Therefore, the 7th floor window is 67.15 m above ground level.
5 0
3 years ago
The electric field direction is defined by the direction of the force felt by (select one of the following answers):A. A negativ
steposvetlana [31]

Answer:

B

Explanation:

The formula for the electric field is Force (N)/charge(Coulombs). The electric field direction is defined by the direction of the force felt by a positive charge.

4 0
4 years ago
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