Answer:
The acceleration is 0.133 m/s²
The time taken to build the final speed is 219.32 s
Explanation:
Given;
final speed of the cyclist, v = 105 km/h = 29.17 m/s²
distance traveled by the cyclist, d = 3.2 km = 3,200 m
initial speed, u = 0
Apply the following kinematic equation to determine the acceleration of the cyclist;
v² = u² + 2as
(29.17 )² = 0 + (2 x 3200)a
850.89 = 6400a
a = (850.89 ) / (6400)
a = 0.133 m/s²
The time taken to build up the final speed is given by;
v = u + at
29.17 = 0 + (0.133)t
t = 29.17 / 0.133
t = 219.32 s
The pull of the moon on Earth's tidal bulge is causing The moon to slowly move farther away from the Earth. Hope that helps.
Answer:
d = ( -0.3 , 0.7 ) miles
Explanation:
The complete question is as follows:
" Take the north direction as the positive y direction and east as positive x. The origin is still where the student starts biking. Let d⃗ N be the displacement vector corresponding to the first leg of the student's trip. Express d⃗ N in component form.
Express your answer as two numbers separated by a comma (e.g., 1.0,2.0). By convention, the x component is written first.
A student bikes to school by traveling first dN = 0.800 miles north, then dW = 0.300 miles west, and finally dS = 0.100 miles south. "
Solution:
- The displacement vector d N is vector sum of all journeys. We will express +x as +i and +y as +j. Then displacement vector is given by:
d = dN + dW + dS
d = 0.8 j - 0.3 i - 0.1 j
d = - 0.3 i + 0.7 j
- The displacement vector d in component form is d = ( -0.3 , 0.7 ) miles
Answer:
Mantle will be the required answer
