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Julli [10]
3 years ago
13

What causes the pressure to increase as you go deeper below the crust?

Physics
2 answers:
Masteriza [31]3 years ago
8 0

The deeper you go, the more rock must be supported so the more force is required and the pressure goes up.

enyata [817]3 years ago
7 0

Answer:

Pressure is force per unit area. In this case the force is primarily the weight of the overlying rock. So , in very simple terms, the deeper you go the more rock must be supported so the more force is required and the pressure goes up. It is basically the same thing that happens in the ocean and in the atmosphere.

Explanation:

.

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________ can occasionally cause the North Atlantic to appear green and murky.
castortr0y [4]

Answer:

algae

Explanation:

The Atlantic off the East Coast of the United States usually appears green. This is due to the presence of algae and plant life.

4 0
2 years ago
A tuna fish body is streamlined to reduce friction. Which describes the type of friction the fish must overcome?
STatiana [176]
The answer would be Fluid Friction
7 0
3 years ago
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A disk rotates around an axis through its center that is perpendicular to the plane of the disk. The disk has a line drawn on it
natka813 [3]

Answer:

t = \frac{\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

Explanation:

The rotated angle is given by:

\theta=\omega0*t+1/2*\alpha*t^2

Since this is a quadratic equation it can be solved using:

x=\frac{-b \± \sqrt{b^2-4*a*c}  }{2*a}

Rewriting our equation:

1/2*\alpha*t^2+\omega0*t-\theta=0

t = \frac{\±\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

Since \sqrt{\omega0^2+2*\theta*\alpha} >\omega0 we discard the negative solution.

t = \frac{\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

8 0
3 years ago
A spacecraft and a staellite are at diametrically opposite position in the same circular orbit of altitude 500 km above the eart
Tanya [424]

Answer:

Hello the diagram related to your question is attached below

answer: a) 851 m/s

             b)  8506.1 secs

Explanation:

calculate the periodic time of the satellite using the equation below

t = \frac{2\pi }{R} \sqrt{\frac{(R+h)^{3} }{g} }  --  ( 1 )

where ; R = 6370 km

h = 500 km

g = 9.81 m/s^2

input given values into equation 1

t = 5670.75 secs

next calculate the periodic time taken by the space craft  

<u>a) determine the increase in speed </u>

V = v - \sqrt{\frac{gR^2}{R + h} }  

where ; v = 8463 m/s , R = 6370 km, h = 500 km

V = 851 m/s

b) Determine the periodic time for the elliptic orbit

τ = \frac{3t}{2}

 = \frac{3*5670.76}{2}  =  8506.1 secs

attached below is the remaining part of the detailed solution

5 0
3 years ago
Straight-in spaces can leave you a safer out if
kiruha [24]

Answer:

Explanation:

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4 0
3 years ago
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