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AnnZ [28]
3 years ago
13

A rocket takes off from Earth and reaches a speed of 105 m/s in 18.0 s. If the exhaust speed is 1,200 m/sand the mass of fuel bu

rned is 110 kg, what was the initial mass (in kg, including the initial fuel) of the rocket?
Physics
1 answer:
Amanda [17]3 years ago
7 0

Answer:

The initial mass of the rocket is 526.2 kg.

Explanation:

Given that,

Final speed = 105 m/s

Time = 18.0 s

Exhaust initial speed = 1200 m/s

Mass of burned fuel = 110 kg

We need to calculate the initial mass

The velocity change of rocket under gravity is defined as,

v=u\ ln(\dfrac{m_{i}}{m})-gt....(I)

We know that,

m=m_{i}-m_{bf}

Put the value of m in equation (I)

v=u\ ln(\dfrac{m_{i}}{m_{i}-m_{bf}})-gt

m_{i}=\dfrac{m_{bf}}{1-e^-{\dfrac{v+gt}{u}}}

m_{i}=\dfrac{110}{1- e^-{\frac{105+9.8\times18}{1200}}}

m_{i}=526.2 kg

Hence, The initial mass of the rocket is 526.2 kg.

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Mrac [35]

Answer:

d. 3332.5 [N]

Explanation:

To solve this problem we will use newton's second law, which tells us that the sum of forces is equal to the product of mass by acceleration.

Here we have two forces, the force that pushes the car to move forward and the friction force.

The friction force is equal to the product of the normal force by the coefficient of friction.

f = N * μ

f = (m*g) * μ

where:

N = weight of the car = 2150*9.81 = 21091.5 [N]

μ = 0.25

f = (21091.5) * 0.25

f = 5273 [N]

Now as the car is moving forward, the car wheels move clockwise. The friction force between the wheels of the car and the pavement must be counterclockwise, i.e. counterclockwise. Therefore the direction of this force is forward. This way we have:

F + f = m*a

F + 5273 = 2150*4

F = 8600 - 5273

F = 3327 [N]

Therefore the answer is d.

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2 years ago
How would the gravitational force between the earth and the moon change if the moon had half the mass?
Vikki [24]

The moon's gravity, combined with the waltz of Earth and the moon around their center of mass, forces the oceans into an oval shape, with two simultaneous high tides. ... If the moon were half its mass, then the ocean tides would have been correspondingly smaller and imparted less energy to it.

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3 years ago
What is the acceleration of a 5kg mass pushed by a 10N force?
dem82 [27]

Answer:2m/s^2

Explanation:

mass=5kg

Force=10N

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2 years ago
Sherlock Holmes examines a clue by holding his magnifying glass (with
Alborosie

Answer:

Distance: -30.0 cm; image is virtual, upright, enlarged

Explanation:

We can find the distance of the image using the lens equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where:

f = 15.0 cm is the focal length of the lens (positive for a converging lens)

p = 10.0 cm is the distance of the object from the lens

q is the distance of the image from the lens

Solving for q,

\frac{1}{q}=\frac{1}{f}-\frac{1}{q}=\frac{1}{15.0}-\frac{1}{10.0}=-0.033\\q=\frac{1}{0.033}=-30.0 cm

The negative sign tells us that the image is virtual (on the same side of the object, and it cannot be projected on a screen).

The magnification can be found as

M=-\frac{q}{p}=-\frac{-30}{10}=3

The magnification gives us the ratio of the size of the image to that of the object: since here |M| = 3, this means that the image is 3 times larger than the object.

Also, the fact that the magnification is positive tells us that the image is upright.

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Which type of wave does NOT have a crest?
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You answer is b an oscillating wave
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