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3 years ago

What would happen if uranium-241 lost 2 protons and 2 neutrons?

1 answer:

5 0

If uranium-241 lost 2 protons and 2 neutrons, then thorium-237 would be produced. The number beside the element is the mass number which is the sum of protons and neutrons. If uranium would lose 2 protons and 2 neutrons, then the mass number would decrease by 4 making it 237. Looking in a periodic table, thorium is the element which has a mass number of 237.

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How many moles of oxygen are in 2.00 moles of NaCIO4?

Klio2033 [76]

Answer: 8 Moles of Oxygen

Explanation: The formula shows that there are (exactly) 4 oxygen atoms in each mole or formula unit. Therefore 4 * 2.00 = 8.

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3 years ago

Name the laws for 1,2, and 3

BaLLatris [955]

Answer:

1. Boyle's law

2. Charle's law

3. Ideal Gas law

Explanation:

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3 years ago

Which is longer, the carbon-oxygen single bond in a carboxylic acid or the carbon-oxygen bond in an alcohol?

Nikolay [14]

The carbon-oxygen single bond in a carboxylic acid

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3 years ago

Need help !!!!! ASAP

Julli [10]

<h2>Hello!</h2>

The answer is:

The new volume will be 1 L.

$V_{2}=1L$

To solve the problem, since we are given the volume and the first and the second pressure, to calculate the new volume, we need to assume that the temperature is constant.

To solve this problem, we need to use Boyle's Law. Boyle's Law establishes when the temperature is kept constant, the pressure and the volume will be proportional.

Boyle's Law equation is:

$P_{1}V_{1}=P_{2}V_{2}$

So, we are given the information:

$V_{1}=2L\\P_{1}=50kPa\\P_{2}=100kPa$

Then, isolating the new volume and substituting into the equation, we have:

$P_{1}V_{1}=P_{2}V_{2}$

$V_{2}=\frac{P_{1}V_{1}}{P_{2}}$

$V_{2}=\frac{50kPa*2L}{100kPa}=1L$

Hence, the new volume will be 1 L.

$V_{2}=1L$

Have a nice day!

4 0

3 years ago

Using the accepted value for the volume of 1 gram of water at the temperature of the room that you reported above, what is the a

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3 years ago