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ololo11 [35]
3 years ago
14

If 3.13 mol of an ideal gas has a pressure of 2.33 atm and a volume of 72.31 L, what is the temperature of the sample in degrees

Celsius?
Chemistry
1 answer:
Ratling [72]3 years ago
8 0

Answer:

382.49 C degree Celsius

Explanation:

Hello,

This problem deals with understanding the ideal gas law which hopes to predict how ideal gases might behave in any given condition. I listed the formula below and we are basically just going to solve for temperature by rearranging the equation as seen on the picture (there's also other rearranged ones in case you need to solve for those).

Universal gas constant R has a value of 0.0821 L * atm/(mole * K) when working with these given units so it will be part of this equation. R value changes based on what units you have.

T = PV/nR

   = (2.33) (72.31) / (3.13)(0.0821)

   = 655.64 K

Question is asking temperature in celsius so we employ the formula attached below:

C = K - 273.15

   = 655.64-273.15

    = 382.49 degree Celsius

382.49 degree Celsius is the answer!

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its 0.163 g

Explanation:

From the total pressure and the vapour pressure of water we can calculate the partial pressure of O2​

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From the ideal gas equation we write.

W= RT/PVM = (0.0821Latm/Kmol)(273+24)K(0.974atm)(0.128L)(32.0g/mol/) =0.163g

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2 years ago
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A student is preparing to perform a series of calorimetry experiments. She first wishes to determine the calorimeter constant (C
laila [671]

Answer:

  • First choice: 99 J/K

Explanation:

<u>1) First law of thermodynamic (energy balance)</u>

  • Heat released by the the hot water (345K ) = Heat absorbedby the cold water (298 K) + Heat absorbed by the calorimeter

<u>2) Energy change of each substance:</u>

  • General formula:

     

Heat released or absorbed = mass × Specific heat × change in temperature

  • density of water: you may take 0.997 g/ ml as an average density for the water.

  • mass of water: mass = density × volume = 50.0 ml × 0.997 g/ml = 49.9 g

  • Specif heat of water: 1 cal / g°C

  • Heat released by the hot water:

       Heat₁ = 49.9 g × 1 cal / g°C × (345 K - 317 K) = 49.9 g × 1 cal / g°C × (28K)

  • Heat absorbed by the cold water:

       Heat₂ = 49.9 g × 1 cal / g°C × (317 K - 298 K) = 49.9 g × 1 cal / g°C × (19K)

  • Heat absorbed by the calorimeter

       Heat₃ = Ccal × (317 K - 298 K) = Ccal × (19K)

<u>4) Balance</u>

  • Heat₁ = Heat₂ + Heat₃

49.9 g × 1 cal / g°C × (28 K) = 49.9 g × 1 cal / g°C × (19 K) + Ccal × (19 K)

  • Solve for Ccal

Ccal = [49.9 g × 1 cal / g°C × (28 K) - 49.9 g × 1 cal / g°C × (19 K) ] / 19K

Ccal = 23.6 cal/ K

  • Convert to cal / K to Joule / K

  • 1 cal = 4.18 Joule

       23.6 cal / K × 4.18 J / cal = 98.6 J/K

Which rounded to 2 signficant figures leads to 99 J/k, which is the first choice.

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Are alchemy and chemistry the same: No

<u>Explanation:</u>

Alchemy and chemistry differ from each other. Their main difference lies in the concepts that they are based on. Alchemy has the base of viewing the reality of nature supernaturally. Chemistry has a base of viewing the reality in a natural way.

Protoscience is the name given for Alchemy. This is because that alchemy usually focuses on the traditional things like procedures and  terminologies. Chemistry always focuses on the matter and their transformations. The matter and its transformations are dealt with chemistry.

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