Find molar mass of MgCl2 so M=<span>95.211 g/mol
N=m/M
N=332/95.2
N=3.487
dont forget to round your sig figs </span>
Answer:
sodium
Explanation:
this is because sodium is neutral ....hence the pH formed will be 7
Answer:
the shape of a piece of matter can change
Answer:
0.294 M
Explanation:
The computation of the final molarity of acetate anion is shown below:-
Lead acetate = Pb(OAc)2
Lead acetate involves two acetate ion.
14.3 gm lead acetate = Mass ÷ Molar mass
= 14.3 g ÷ 325.29 g/mol
= 0.044 mole
Volume of solution = 300 ml.
then
Molarity of lead is
= 0.044 × 1,000 ÷ 300
= 0.147 M
Therefore the molarity of acetate anion is
= 2 × 0.147
= 0.294 M
Answer:
0.43×10²³ atoms
Explanation:
Given data:
Mass of LiBrO₂ = 4.28 g
Number of atoms of oxygen = ?
Solution:
Number of moles = mass/molar mass
Number of moles = 4.28 g/ 118.84 g/mol
Number of moles = 0.036 mol
We can see 1 mole of LiBrO₂ contain 2 mole of oxygen atm.
0.036 mol × 2 = 0.072 mol
1 mole contain 6.022×10²³ atoms
0.072 mol × 6.022×10²³ atoms / 1mol
0.43×10²³ atoms
