According to this formula:
(P1V1) / T1 = (P2V2) / T2
convert T from C° to Kelvin:
T1 = 83 + 273 = 356 K
T2= 96 + 273 = 369 K
convert P from torr to atm:
1 torr = 0.00131578947 atm<span>
p1 = 0.839474 atm
P2 = 1.415789 atm
By substitution in the previous formula:
(0.839474 x 10.6 ) / (356) = ( 1.415789 x V2 ) / 369
So:
V2 = 6.5 L</span>
Answer:
B
Explanation:
Cuz they are supported once discovered and then widely spread then accepted
Answer:
The mass of coke needed to react completely with 1.0 ton of copper(II) oxide is 0.794 Ton.
Explanation:

1 Ton = 907185 grams
Mass of copper oxide = 1.0 Ton = 907185 grams
Moles of copper oxide =
According to reaction, 2 moles of copper oxide reacts with 1 mole of carbon.
Then 11403.95 moles of copper oxide will react with:
of carbon
Mass of 5,701.98 moles of carbon:

Mass of coke = x
Mass of carbon = 68,423.75 g
Percentage of carbon in coke = 95%


The mass of coke needed to react completely with 1.0 ton of copper(II) oxide is 0.794 Ton.
Answer:
A calculator has an endifiite shape because all of its atoms are touching each other
Answer:
0.054 mol O
Explanation:
<em>This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): CH₃CO₂H. An analytical chemist has determined by measurements that there are 0.054 moles of carbon in a sample of acetic acid. How many moles of oxygen are in the sample?</em>
<em />
Step 1: Given data
- Chemical formula of acetic acid: CH₃CO₂H
- Moles of carbon in the sample: 0.054 moles
Step 2: Establish the appropriate molar ratio
According to the chemical formula, the molar ratio of C to O is 2:2.
Step 3: Calculate the moles of oxygen in the sample
We will use the molar ratio to determine the moles of oxygen accompanying 0.054 moles of carbon.
0.054 mol C × (2 mol O/2 mol C) = 0.054 mol O