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Viefleur [7K]
3 years ago
10

Here you go rats....

Chemistry
2 answers:
luda_lava [24]3 years ago
8 0

Answer:

what!!!??????

defon3 years ago
4 0

Answer: Why exacly am i a rat

Explanation:

,....

but thanks

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if 0.0203 g of a gas dissolves in 1.39 l of water at 1.02 atmospheres at what pressure (in atm) would you be able to dissolve 0.
Sergeu [11.5K]
First, we need to get n1 (no.of moles of water ): when

mass of water = 0.0203 g and the volume = 1.39 L

∴ n1 = mass / molar mass of water

        = 0.0203g / 18 g/mol
        = 0.00113 moles

then we need to get n2 (no of moles of water) after the mass has changed:

when the mass of water = 0.146 g

n2 = mass / molar mass

     = 0.146g / 18 g/ mol
     = 0.008 moles

so by using the ideal gas formula and when the volume is not changed:

So, P1/n1 = P2/n2 

when we have P1 = 1.02 atm 

and n1= 0.00113 moles

and n2 = 0.008 moles 

so we solve for P2 and get the pressure

∴P2 = P1*n2 / n1

        =1.02 atm *0.008 moles / 0.00113 moles

       = 7.22 atm

∴the new pressure will be 7.22 atm


5 0
3 years ago
The primary gas in a volocano is?
stiv31 [10]

Answer:

By far the most abundant volcanic gas is water vapor, which is harmless. However, significant amounts of carbon dioxide, sulfur dioxide, hydrogen sulfide and hydrogen halides can also be emitted from volcanoes

Explanation:

4 0
3 years ago
Read 2 more answers
A boy weighing 25 kg sits in a 1000 kg car at a speed of 15 m/s. What is the total momentum of the car and the boy?
dexar [7]

Answer:

D) 15375kgm/s

Explanation:

weight of the boy 25kg +weight of the car 1000kg= 1025kg so momentum =mass × velocity. so it's SI unit is = kg×m/s = kg m/s.

7 0
3 years ago
1. Calculate the attractive bonding force for NaF and for MgO when the ions just touch. Based on the attractive bonding force, w
Andreas93 [3]

Answer:

The attractive force is negative and MgO has a higher melting point

Explanation:

From Couloumb's law:

Energy of interaction, E = k \frac{q1q2}{r}

where q1 and q2 are the charges of the ions, k is Coulomb's constant and r is the distance between both ions, i.e the atomic radii of the ions.

If you look at Coulomb's law, you note that in the force is negative (because q1 is negative while q2 is positive).

In addition to that, the compounds MgO and NaF have similar combined ionic radii, then we can determine the melting point trend from the amount of energy gotten

The melting point of ionic compounds is determined by 1. charge on the ions 2. size of ions. while NaF has smaller charges (+1 and -1), MgO (+2 and -2) has larger charges and greater combined atomic radii. This implies that the compound with greater force would have a higher melting point.

Hence the compound MgO would have a higher melting point than NaF.

5 0
4 years ago
A 160g radioactive sample is left undisturbed for 12.5 hours. At the end of that period, only 5.0g remain. What is the half-life
11Alexandr11 [23.1K]

it would be 26 because once you divide 160g by 5.0g and add 12.5 you would get 26

hope this helps

3 0
3 years ago
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