Here is the full question.
What is the pH of a solution that results when 0.010 mol HNO3 is added to 500 mL of a solution that is 0.10 M in aqueous ammonia and 0.20 M in ammonium nitrate? Assume no volume change. The Kb of ammonia is 1.8*10^-5.
Answer:
8.82
Explanation:
Volume = 500 mL = 0.500 L
Number of moles of NH₃ = 0.10 mole × 0.500 L = 0.050 moles
Number of moles of NH₄⁺ = 0.20 mole × 0.500 L = 0.10 moles
NH₃ + H⁺ ----------> NH₄⁺
In 0.010 mole of HNO₃ ;
Number of moles of NH₃ = 0.050 moles - 0.010 moles
= 0.040 moles
Number of moles of NH₄⁺ = 0.10 moles + 0.010 = 0.11 moles
Concentration of NH₃ = 
= 
= 0.080 M
Concentration of NH₃ = 
= 
= 0.220 M
NH₃ + H₂O ⇄ NH₄⁺ + OH⁻
Initial 0.080 M 0 0.220 M 0
Change -x +x x
Equilibrium 0.080 -x 0.220 +x x
= 
= 
x = [OH⁻] = 6.55 × 10⁻⁶ M
pOH = 5.18
pH + pOH = 14
pH = 14 - pOH
pH = 14 - 5.18
pH = 8.82
Answer:
Pb (NO₃)₂(aq) + 2KCl(aq) → 2KNO₃(aq) + PbCl₂(s)
Explanation:
In given chemical equation the aqueous lead (II) nitrate react with aqueous potassium chloride and form aqueous potassium nitrate and lead chloride.
Chemical equation:
Pb (NO₃)₂(aq) + KCl(aq) → KNO₃(aq) + PbCl₂(s)
Balanced chemical equation:
Pb (NO₃)₂(aq) + 2KCl(aq) → 2KNO₃(aq) + PbCl₂(s)
ionic equation:
Pb²⁺ (aq) + 2NO₃⁻ (aq) + 2K⁺(aq) + 2Cl⁻ (aq) → 2NO₃⁻(aq) + 2K⁺(aq) + PbCl₂(s)
Net ionic equation:
Pb²⁺ (aq) + 2Cl⁻ (aq) → PbCl₂(s)
The NO₃⁻(aq) and K⁺(aq) are spectator ions that's why these are not written in net ionic equation. The PbCl₂ can not be splitted into ions because it is present in solid form.
Spectator ions:
These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.
The answer is (1) CaCO3. The bond between C and O is covalent bond. And the bond between Ca2+ and CO3 2- ion is the ionic bond. So the compound CaCO3 satisfy this condition.
Answer:
1085° C
Explanation:
From the phase diagram of Ag-Cu shown below:
The minimum value of the high-temp required to be selected for the furnace is: 1085° C
This is on the grounds that the furnace should be chosen to such an extent that it should melt any sort of possible material including pure Cu that melts and liquefies at the temperature of 1085° C.