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Lady bird [3.3K]
3 years ago
6

What is the product of the polynomial below? (8 - x2)(x - x3) A.x5 - 9x3 + 6x B.x5 + 9x3 + 6x C.x5 + 9x3 + 8x D.x5 - 9x3 + 8x

Mathematics
1 answer:
kumpel [21]3 years ago
4 0
Combine like terms to: x^5-9x^3+8x. So the Answer is D
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9. Find P(rolling 1 or 5) with one number cube.
marta [7]

Answer:

1/3

Step-by-step explanation:

There are 6 possible outcomes when rolling 1 die

1,2,3,4,5,6

P ( 1 or 5) = number of times 1 or 5 happens / total outcomes

               = 2/ 6

               = 1/3

6 0
4 years ago
WILL GIVE BRAINLIEST!!!
Salsk061 [2.6K]

Three reasons why the other method is not better is because to use drawing program would mean you would need some sort of technology and electricity to use it and some places, like third world countries, do not have access to that, so most probably you would have to resort to paper. Also, drawing programs are based off the skills needed to create geometric figures with a straightedge and compass. And lastly, what if we had no more technology anymore? Then how would we use a drawing program? Drawing programs are only reliable when electricity is located.

SO THE ANSWER IS A hope it help :)

5 0
3 years ago
Read 2 more answers
At last weekend's football game, 15 out of the first 50 people who entered the field were wearing hats.
Mariana [72]

Answer:

C.  75 people

Step-by-step explanation:

50x5=250

15x5 = 75

so, 75 people

4 0
3 years ago
Read 2 more answers
Two major automobile manufacturers have produced compact cars with engines of the same size. We are interested in determining wh
Molodets [167]

Answer:

(A) The mean for the differences is 2.0.

(B) The test statistic is 1.617.

(C) At 90% confidence the null hypothesis should not be rejected.

Step-by-step explanation:

We are given that a random sample of eight cars from each manufacturer is selected, and eight drivers are selected to drive each automobile for a specified distance.

The following data (in miles per gallon) show the results of the test;

Driver         Manufacturer A               Manufacturer B

   1                      32                                       28

  2                      27                                       22

  3                      26                                       27

  4                      26                                       24

  5                      25                                       24

  6                      29                                       25

  7                       31                                       28

  8                      25                                       27

Let \mu_1 = mean MPG for the fuel efficiency of Manufacturer A brand

\mu_2 = mean MPG for the fuel efficiency of Manufacturer B brand

SO, Null Hypothesis, H_0 : \mu_1-\mu_2=0  or  \mu_1= \mu_2    {means that there is a not any significant difference in the mean MPG (miles per gallon) when testing for the fuel efficiency of these two brands of automobiles}

Alternate Hypothesis, H_A : \mu_1-\mu_2\neq 0  or  \mu_1\neq  \mu_2   {means that there is a significant difference in the mean MPG (miles per gallon) for the fuel efficiency of these two brands of automobiles}

The test statistics that will be used here is <u>Two-sample t test statistics</u> as we don't know about the population standard deviations;

                      T.S.  = \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }  ~ t__n__1+_n__2-2

where, \bar X_1 = sample mean MPG for manufacturer A = \frac{\sum X_A}{n_A} = 27.625

\bar X_2 = sample mean MPG for manufacturer B =\frac{\sum X_B}{n_B} = 25.625

s_1 = sample standard deviation for manufacturer A = \sqrt{\frac{\sum (X_A-\bar X_A)^{2} }{n_A-1} } = 2.72

s_2 = sample standard deviation manufacturer B = \sqrt{\frac{\sum (X_B-\bar X_B)^{2} }{n_B-1} } = 2.20

n_1 = sample of cars selected from manufacturer A = 8

n_2 = sample of cars selected from manufacturer B = 8

Also, s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} }   =  \sqrt{\frac{(8-1)\times 2.72^{2}+(8-1)\times 2.20^{2}  }{8+8-2} }  = 2.474

(A) The mean for the differences is = 27.625 - 25.625 = 2

(B) <u><em>The test statistics</em></u>  =  \frac{(27.625-25.625)-(0)}{2.474 \times \sqrt{\frac{1}{8}+\frac{1}{8}  } }  ~  t_1_4

                                     =  1.617

(C) Now at 10% significance level, the t table gives critical values between -1.761 and 1.761 at 14 degree of freedom for two-tailed test. Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is a not any significant difference in the mean MPG (miles per gallon) when testing for the fuel efficiency of these two brands of automobiles.

5 0
4 years ago
A little help please
Nimfa-mama [501]

Answer:

I think it is yes.

Step-by-step explanation:

8 0
3 years ago
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