Test for symmetry about the x-axis: Replace y with (-y). Simplfy the equation. If the resulting equation is equivalent to the original equation then the graph is symmetrical about the x-axis. Example: Use the test for symmetry about the x-axis to determine if the graph of y - 5x2 = 4 is symmetric about the x-axis.
Test for symmetry about the y-axis: Replace x with (-x). Simplfy the equation. If the resulting equation is equivalent to the original equation then the graph is symmetrical about the y-axis. Example: Use the test for symmetry about the y-axis to determine if the graph of y - 5x2 = 4 is symmetric about the y-axis.
I didn't fully understand the question but this is the best I can do! Hope this helps! :D
Answer:
(2.5 , 3.5)
Step-by-step explanation:
We can use the midpoint formula . Here the points are , (2,2) and (3,5) .
• <u>Using</u><u> </u><u>Midpo</u><u>int</u><u> Formula</u><u> </u><u>:</u><u>-</u><u> </u>
⇒ M = { (x1 + x2)/2 , (y1 + y2)/2 }
⇒ M = ( 2+3/2 , 5+2/2 )
⇒ M = ( 5/2 , 7/2 )
⇒ M = ( 2.5 , 3.5 )
<h3>
<u>Hence </u><u>the</u><u> </u><u>midpoint</u><u> </u><u>is</u><u> </u><u>(</u><u>2</u><u>.</u><u>5</u><u> </u><u>,</u><u> </u><u>3</u><u>.</u><u>5</u><u>)</u></h3>
Simplify:
7x+3=7x-3
Now 7x goes away and you get 3=-3, which cannot be true, so there is no solution
Answer:
7/10 and 7/8 are both less than 1.
Step-by-step explanation:
The product must be less than either factor because when you multiply a number by less than 1, the number gets smaller.

Substitute this into the parabolic equation,

We're told the line
intersects
twice, which means the quadratic above has two distinct real solutions. Its discriminant must then be positive, so we know

We can tell from the quadratic equation that
has its vertex at the point (3, 6). Also, note that

and

so the furthest to the right that
extends is the point (5, 2). The line
passes through this point for
. For any value of
, the line
passes through
either only once, or not at all.
So
; in set notation,
