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frez [133]
3 years ago
6

A car drives 16 miles south and then 12 miles west. What is the magnitude of the car’s displacement? 4 miles 16 miles 20 miles 2

8 miles
Physics
2 answers:
Ostrovityanka [42]3 years ago
7 0
For this case, what we can do is use the Pythagorean theorem to find the magnitude of the displacement of the car.
 We have then
 d ^ 2 = 16 ^ 2 + 12 ^ 2

 From here, we clear the value of d.
 We have then:
 d =  \sqrt{16 ^ 2 + 12 ^ 2} 

 Rewriting:
 d = \sqrt{256 + 144}
 d = \sqrt{400}
 d = 20 miles

 Answer:
 
The magnitude of the car's displacement is:
 
d = 20 miles
Lilit [14]3 years ago
3 0
20 miles. just took the quiz.
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The time delay between the arrival of the two pulses at the ceiling is 2.33 ms.

<h3>What is center of gravity?</h3>

Any object of mass is attracted towards another by point where whole mass is supposed to be concentrated is called center of gravity.

A 1750 N irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (A and B), each 1.25 m long and weighing 0.290 N.

The center of gravity of this beam is one-third of the way along the beam from the end where wire A is attached.

Taking moments about one end, to find the tension at other end.

Tb X L = WxL/3

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and
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here, Ta is the tension in end A.

Substitute the values, we get

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Velocity of end A, Va = (1166.66 x1.25 x 9.81/0.290 )^(1/2)

Va = 222 m/s

Velocity of end B, Vb = (583.33 x1.25 x 9.81/0.290 )^(1/2)

Va = 157 m/s

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Substitute the values, we get

t= 0.00233 s

t = 2.33 ms

Thus, time delay between the arrival of the two pulses at the ceiling is 2.33 ms.

Learn more about center of gravity.

brainly.com/question/20662235

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