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3 years ago

12

Everybody can you post the lyrics to your favorite song? I'll give brainliest if I know the song or if I like the lyrics, I'll b

e doing a few of these so.... yeah have fun!>

2 answers:

Setler [38]3 years ago

5 0

Answer:

I cant post da lyrics lol but this is the song

Explanation:

chill bill by rob stone feat. J. Davis and spooks

andrezito [222]3 years ago

4 0

Answer:

Show and tell

I'm on display for all you (bad word) to see

Show and tell

Harsh words if you don't get a pic with me

Buy and sell (buy and sell me, baby)

Like I'm a product to society

Art don't sell

Unless you (bad word) every authority

Explanation:

You might be interested in

a 46 kilogram student climbs 11 meter up a rope at a constant speed if the student power output is 230 watts how long in seconds

Bezzdna [24]

230×46=10580÷11=961 second

3 0

3 years ago

The Heaviside function H is defined by H(t)={0 if t<0, 1 if t≥0 It is used in the study of electric circuits to represent the

Studentka2010 [4]

Answer:

$V(t)= 240V* H(t-5)$

Explanation:

The heaviside function is defined as:

$H(t) =1 \quad t\geq 0\\H(t) =0 \quad t$

so we see that the Heaviside function "switches on" when $t=0$ , and remains switched on when $t>0$

If we want our heaviside function to switch on when $t=5$ , we need the argument to the heaviside function to be 0 when $t=5$

Thus we define a function f:

$f(t) = H(t-5)$

The $-5$ term inside the heaviside function makes sure to displace the function 5 units to the right.

Now we just need to add a scale up factor of 240 V, because thats the voltage applied after the heaviside function switches on. ( $H(t-5) =1$ when $t\geq 5$ , so it becomes just a 1, which we can safely ignore.)

Therefore our final result is:

$V(t)= 240V* H(t-5)$

I have made a sketch for you, and added it as attachment.

5 0

3 years ago

You push a coin across a table. The coin stops. How does this motion relate to balanced and unbalanced forces?

Snezhnost [94]

If you are pushing the coin across the table at a constant rate, the friction of the table and the horizontal force of your hand pushing are equal, and the coin itself moves at a constant rate. If you push a coin and let it go, there is no horizontal force keeping the coin going. Friction slows the coin to a stop. In both cases, the gravitational downward pull of Earth is equally but oppositely resisted by the upward push of table on the coin.

7 0

3 years ago

You drop a 20 Ton object and a

Alborosie

Explanation:

it dosent depend on the weights of the items. I'll reach the ground at same time taking as no air friction or restrictions.

i.e

v = u + gt

whte v is final velocity of the object

u is initial velocity of the object

g is acceleration due to gravity and

t is time. thanks

please if found helpful rate brainliest

7 0

2 years ago

A potential difference of 53 mV is developed across the ends of a 12.0-cm-longwire as it moves through a 0.27 T uniform magnetic

Klio2033 [76]

Answer:

The angle between the magnetic field and the wire’s velocity is 19.08 degrees.

Explanation:

Given that,

Potential difference, V = 53 mV

Length of the wire, l = 12 cm = 0.12 m

Magnetic field, B = 0.27 T

Speed of the wire, v = 5 m/s

Due to its motion, an emf is induced in the wire. It is given by :

$\epsilon=Blv\sin\theta$

Here,

$\theta$ is the angle between magnetic field and the wire’s velocity

$\sin\theta=\dfrac{\epsilon}{Blv}\\\\\sin\theta=\dfrac{53\times 10^{-3}}{0.27\times 0.12\times 5}\\\\\sin\theta=0.327\\\\\theta=19.08^{\circ}$

So, the angle between the magnetic field and the wire’s velocity is 19.08 degrees.

8 0

3 years ago