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maks197457 [2]
4 years ago
13

A person can jump 1.5m on the earth. How high could the person jump on a planet having the twice the mass of the earth and twice

the radius of the earth?
Physics
2 answers:
guapka [62]4 years ago
8 0
I believe you'd have to calculate the different planets info and use the formula you the problem used to find their height of the jump in order to find yours ..
MrMuchimi4 years ago
5 0
F=mg=Gm1m2/r^2
g=Gm2/r^2
g=2Gm2/(2r)^2=2Gm2/4r^2=Gm2/2r^2
So since there is half times the gravity on this unknown planet that has twice earth's mass and twice it's radius, then the person can jump twice as high. 1.5*2= 3m high

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Por una tubería de 0.06 m de diámetro circula agua con una velocidad desconocida, al llegar a la parte estrecha de la tubería de
Vesnalui [34]

Answer:

La velocidad con la que se desplaza el agua antes de llegar a la parte estrecha de la tubería es 1.156 \frac{m}{s}

Explanation:

La ecuación de continuidad es simplemente una expresión matemática del principio de conservación de la masa.  Este principio establece que la masa de un objeto o colección de objetos nunca cambia con el tiempo.

La ecuación de continuidad es la relación que existe entre el área y la velocidad que tiene un fluido en un lugar determinado y dice que el caudal de un fluido es constante a lo largo de un circuito hidráulico.

En otras palabras, la ecuación de continuidad se basa en que el caudal (Q) del fluido ha de permanecer constante a lo largo de toda la conducción. Cuando un fluido fluye por un conducto de diámetro variable, su velocidad cambia debido a que la sección transversal varía de una sección del conducto a otra.

Entonces, siendo el caudal es el producto de la superficie de una sección del conducto por la velocidad con que fluye el fluido,  en dos puntos de una misma tubería se cumple:

Q1=Q2

A1*v1= A2*v2

donde:

  • A es la superficie de las secciones transversales de los puntos 1 y 2 del conducto.
  • v es la velocidad del flujo en los puntos 1 y 2 de la tubería.

Siendo A=pi*r^{2} =pi*(\frac{D}{2} )^{2} =\frac{pi*D^{2} }{4} , donde pi es el número π, r es el radio del conducto y D el diámetro del conducto, entonces:

\frac{pi*D1^{2} }{4}*v1=\frac{pi*D2^{2} }{4}*v2

En este caso:

  • D1: 0.06 m
  • v1: ?
  • D2: 0.04 m
  • v2: 2.6 m/s

Reemplazando:

\frac{pi*(0.06m)^{2} }{4}*v1=\frac{pi*(0.04m)^{2} }{4}*2.6\frac{m}{s}

Resolviendo:

v1=\frac{\frac{pi*(0.04m)^{2} }{4}*2.6\frac{m}{s}}{\frac{pi*(0.06m)^{2} }{4}}

v1=\frac{(0.04m)^{2} }{(0.06m)^{2}  }*2.6\frac{m}{s}

v1= 1.156 \frac{m}{s}

<u><em>La velocidad con la que se desplaza el agua antes de llegar a la parte estrecha de la tubería es 1.156 </em></u>\frac{m}{s}<u><em></em></u>

8 0
3 years ago
Where will you find the most kinetic energy? ice or water?​
const2013 [10]

Answer:

Water has more kinetic energy because it is liquid, as ice is harder, so it's cells can't move as much.

7 0
3 years ago
Read 2 more answers
At a local swimming pool, the diving board is elevated h = 9.5 m above the pool's surface and overhangs the pool edge by L = 2 m
eimsori [14]

Answer:

1) The time it takes the diver to move off the end of the diving board to the pool surface, t_w, is approximately 1.392 seconds

2) The horizontal distance from the edge of the pool to where the diver enters the water, d_w, is approximately 5.76 meters

Explanation:

1) The given parameters are;

The height of the diving board above the pool's surface, h = 9.5 m

The length by which the diving board over hangs the pool L = 2 m

The speed with which the diver runs horizontally along the diving board, v₀ = 2.7 m/s

Taking t_w = The time it takes the diver to move off the end of the diving board to the pool surface

Therefore, we have from the equation of free fall;

h = 1/2 × g × t_w²

Where;

g = The acceleration due to gravity = 9.81 m/s²

Substituting the values, gives;

9.5 = 1/2 × 9.81 × t_w²

t_w = √(9.5/(1/2 × 9.81)) ≈ 1.392 s

The time it takes the diver to move off the end of the diving board to the pool surface = t_w ≈ 1.392 s

2) The horizontal distance, d_w, in meters from the edge of the pool to where the diver enters the water is given as follows;

d_w = L + v₀ × t_w = 2 + 2.7× 1.392 ≈ 5.76 m

∴ The horizontal distance from the edge of the pool to where the diver enters the water ≈ 5.76 meters.

7 0
3 years ago
If a piece of wood dropped from a tall building has rezched a velocity of 68.6 m/s , how long has it been falling
notsponge [240]

It takes 7.0s for a piece of wood to be falling from a tall building in the velocity of 68.6 m/s

<u>Explanation:</u>

v = u + at

68.6 ms^-1 = 0 ms^-1 + (9.8 ms^-2 x t)

t = 68.6 ms^-1 / 9.8 ms^-2

t = 7.0s

It takes 7.0s for a piece of wood to be falling from a tall building in the velocity of 68.6 m/s

7 0
4 years ago
The weight of the North American P-51 Mustang airplane is 10,100 lb and its wing platform area is 233 ft2 . Calculate the wing l
Natali5045456 [20]

Answer

given,

weight of airplane,W = 10,100 lb

Wing area,A = 233 ft²

now,

Wing Loading Calculation in English engineering

        = \dfrac{W}{A}

        = \dfrac{10,100}{233}

        = 43.35 lb/ft²

Wing Loading in SI unit

        = 43.35\times \dfrac{4.448\ N}{1\ lb}\times (\dfrac{1\ ft}{0.3048})^2

        = 2075.51\ N/m^2

Wing loading in kgf/m²

      = \dfrac{2075.51}{9.81}

      = 211.57 kgf/m²

5 0
3 years ago
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