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3 years ago

Fill in the missing words to make the statements about electromagnetic induction true.

Physics

2 answers:

dimaraw [331]3 years ago

8 0

1. current 2. opposite

Ierofanga [76]3 years ago

7 0

Answer:

If the north pole of a magnet is inserted into a solenoid, a <u>Current </u>will be induced in the solenoid. If the magnet is flipped over so that the south pole of the magnet is inserted into the solenoid, the induced current in the wire will flow in the <u>opposite </u>direction.

Explanation:

Law of electromagnetic induction states that an emf is induced when a conducting coil is kept in a changing magnetic field. Due to this, current is produced in the coil. Solenoid is formed when a current carrying coil is used as an electromagnet. When current is passed through the coil, a magnetic field in produced around it. The arrangement can be used in another way. When a magnet is run into the coil, a current is induced. When poles of the magnet is reversed, then inserted, the direction of current reverses.

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tia_tia [17]

Answer:

the angle of incident is 40°

Explanation:

NQ is the normal to the mirror, therefore

angle NQA =90°

PQA = 50°

incident angle = NQA - PQA

90°- 50° = 40°

note that the angle of reflection is equal to the angle of incident

8 0

3 years ago

Hurricane or typhoons occur when large areas of the open ocean soak up heat from the sun t or f

11Alexandr11 [23.1K]

Answer: true

Explanation:

3 0

3 years ago

A specimen of steel has a rectangular cross section 20 mm wide and 40 mm thick, an elastic modulus of 207 GPa, and a Poisson’s r

katrin2010 [14]

Answer:

There's a decrease in width of 2.18 × 10^(-6) m

Explanation:

We are given;

Shear Modulus;E = 207 GPa = 207 × 10^(9) N/m²

Force;F = 60000 N.

Poisson’s ratio; υ =0.30

We are told width is 20 mm and thickness 40 mm.

Thus;

Area = 20 × 10^(-3) × 40 × 10^(-3)

Area = 8 × 10^(-4) m²

Now formula for shear modulus is;

E = σ/ε_z

Where σ is stress given by the formula Force(F)/Area(A)

While ε_z is longitudinal strain.

Thus;

E = (F/A)/ε_z

ε_z = (F/A)/E

ε_z = (60,000/(8 × 10^(-4)))/(207 × 10^(9))

ε_z = 3.62 × 10^(-4)

Now, formula for lateral strain is;

ε_x = - υ × ε_z

ε_x = -0.3 × 3.62 × 10^(-4)

ε_x = -1.09 × 10^(-4)

Now, change in width is given by;

Δw = w_o × ε_x

Where w_o is initial width = 20 × 10^(-3) m

So; Δw = 20 × 10^(-3) × -1.09 × 10^(-4)

Δw = -2.18 × 10^(-6) m

Negative means the width decreased.

So there's a decrease in width of 2.18 × 10^(-6) m

6 0

3 years ago

What is the intensity of a sound with a measured intensity level of 84 db? (i0 = 10-12 w/m2)?

Ivahew [28]

The unit measurement for sound can be expressed in terms of intensity and in decibels. The intensity of sound is the measure of its power over unit area. The common unit of measurement is in decibels. This is commonly used in measuring the extent of noise. The conversion from intensity to the decibel unit is through logarithmic function. The formula is:

dB = 10 log(I/I0), where I0 is 10^-12 Watts per square meter

Substituting the values to the equation,

84 = 10log(I/10^-12)
I = 0.0002512 W/m2

In scientific notation the intensity is 2.512 x 10^-4 W/m^2.

7 0

3 years ago

Consider the standing wave pattern below created by a string fixed at both ends. The string is under a tension of 0.98 N and has

Shalnov [3]

Answer:

11.07Hz

Explanation:

Check the attachment for diagram of the standing wave in question.

Formula for calculating the fundamental frequency Fo in strings is V/2L where;

V is the velocity of the wave in string

L is the length of the string which is expressed as a function of its wavelength.

The wavelength of the string given is 1.5λ(one loop is equivalent to 0.5 wavelength)

Therefore L = 1.5λ

If L = 3.0m

1.5λ = 3.0m

λ = 3/1.5

λ = 2m

Also;

V = √T/m where;

T is the tension = 0.98N

m is the mass per unit length = 2.0g = 0.002kg

V = √0.98/0.002

V = √490

V = 22.14m/s

Fo = V/2L (for string)

Fo = 22.14/2(3)

Fo = 22.14/6

Fo = 3.69Hz

Harmonics are multiple integrals of the fundamental frequency. The string in question resonates in 2nd harmonics F2 = 3Fo

Frequency of the wave = 3×3.69

Frequency of the wave = 11.07Hz

3 0

3 years ago