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strojnjashka [21]
4 years ago
7

How would the electric field at that point be affected if the charge there were doubled?

Physics
2 answers:
creativ13 [48]4 years ago
8 0

Answer:Yes

Explanation:

If the distance between the two charges doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value.

zubka84 [21]4 years ago
5 0

Answer:

1) c. The magnitude of the field would double

2) a. Yes

Explanation:

1) the electric field at a particular point is given as;

E = kq/d^2

Where;

E = Electric field

k = coulomb's constant

q = charge

d = distance

Which implies that electric field is directly proportional to the charge. Therefore, if the charge is doubled and other variables remain constant, the electric field Will be doubled.

2) Electric force F can be expressed mathematically as;

F = kqQ/d^2

Where;

F = the electric force

Which implies that the electric force is directly proportional to the charges. Therefore, when the charge is doubled, the electric force changes.

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A boy flies a kite with the string at a 30∘ angle to the horizontal. The tension in the string is 4.5 N. Part A Part complete Ho
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Answer:

Work done is zero

Explanation:

given data

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WE KNOW THAT

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1. Jen is stepping out of a boat on to a dock. She has one foot on the dock and one foot in
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The same principle applies when you fire a cannon - in the pirate films, you see the body of the cannon forced back as it is fired.

Take it one step further, Henry VIII flagship, “Mary Rose fired all its cannons together one day in a broad side, the opposite force rolled the ship over and sank it.

3 0
3 years ago
9. Una jeringa contiene cloro gaseoso, que ocupa un volumen de 95 mL a una presión de 0,96 atm. ¿Qué presión debemos ejercer en
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Answer:

2.61 atm

Ley de Boyle

Explanation:

P_1 = Presión inicial = 0.96 atm

P_2 = Presión final

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V_2 = Volumen final = 35 mL

En este problema usaremos la ley de Boyle.

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