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strojnjashka [21]
4 years ago
7

How would the electric field at that point be affected if the charge there were doubled?

Physics
2 answers:
creativ13 [48]4 years ago
8 0

Answer:Yes

Explanation:

If the distance between the two charges doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value.

zubka84 [21]4 years ago
5 0

Answer:

1) c. The magnitude of the field would double

2) a. Yes

Explanation:

1) the electric field at a particular point is given as;

E = kq/d^2

Where;

E = Electric field

k = coulomb's constant

q = charge

d = distance

Which implies that electric field is directly proportional to the charge. Therefore, if the charge is doubled and other variables remain constant, the electric field Will be doubled.

2) Electric force F can be expressed mathematically as;

F = kqQ/d^2

Where;

F = the electric force

Which implies that the electric force is directly proportional to the charges. Therefore, when the charge is doubled, the electric force changes.

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How do the tension of the cord and the force of gravity affect a pendulum?
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<em>Force of gravity may not affect a pendulum during its equilibrium state</em>. But  the gravity can affect the pendulum when a force occurs in any direction of the bob connected to the cord that makes a swing sideways. The gravity of pendulum never stops, it always accelerates. So the gravity affects the pendulum acceleration and speed.    

<em>Similarly the tension in the cord will not affect the pendulum</em><em> </em>but if change in the length of the pendulum while keeping other factors constant changes the length of the period of pendulum. longer pendulum swings with lower frequency than shorter pendulums.    


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3 years ago
Read 2 more answers
If the man has initial velocity of 0.4 m/s, acceleration is 0.343 m/s^2, a time of 5.8 seconds, and experimental final velocity
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Answer:

The answer is going to be C.

Explanation:

Trust me. Im an expert in physics

6 0
4 years ago
Marking branliest!
Ivenika [448]

Answer:

D)evaluating a solution

Explanation:

In this scenario, the next logical step would be evaluating a solution. This is because Jasper and Samantha have already identified the problem/need which is that the robot needs to be able to move a 10-gram weight at least 2 meters and turn in a circle. They also designed and implemented a solution because they have already built the robot. Therefore the only step missing is to evaluate and make sure that the robot they built is able to complete the requirements.

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4 years ago
An air bubble of volume 20 cm³ is at the bottom of a lake 40 m deep, where the temperature is 4.0°C. The bubble rises to the sur
soldi70 [24.7K]

Answer:

100 cm³

Explanation:

Use ideal gas law:

PV = nRT

where P is absolute pressure, V is volume, n is number of moles, R is ideal gas constant, and T is absolute temperature.

n and R are constant, so:

P₁V₁/T₁ = P₂V₂/T₂

If we say point 1 is at 40m depth and point 2 is at the surface:

P₂ = 1.013×10⁵ Pa

T₂ = 20°C + 273.15 = 293.15 K

P₁ = ρgh + P₂

P₁ = (1000 kg/m³ × 9.8 m/s² × 40 m) + 1.013×10⁵ Pa

P₁ = 4.933×10⁵ Pa

T₁ = 4.0°C + 273.15 = 277.15 K

V₁ = 20 cm³

Plugging in:

(4.933×10⁵ Pa) (20 cm³) / (277.15 K) = (1.013×10⁵ Pa) V₂ / (293.15 K)

V₂ = 103 cm³

Rounding to 1 sig-fig, the bubble's volume at the surface is 100 cm³.

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3 years ago
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