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Alik [6]
3 years ago
12

How are distant regions of the universe similar to space near earth

Chemistry
1 answer:
Sergeu [11.5K]3 years ago
3 0
<span>The distant regions of the Universe look older than the space near the Earth. The more distant are, the older is. But the information we can have is lesser due to the distance.</span>
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What particle limitation to the widespread of this reusable water bottles? Pls help someone
Sauron [17]

Answer: Plastic water bottles

Explanation:

If you use disposable water bottles, here are some important concerns you should know about how they’re made as well as the problems they cause for the planet, your health, and your wallet.

3 0
3 years ago
Use mathematics to prove that the 5.50 grams of salicylic acid (C7H6O3) used in this experiment is equal to 0.04 mol.
g100num [7]

Answer:

Please find the answer to the question below

Explanation:

In chemistry, the following mathematical formula is used to calculate the number of moles contained by a substance:

mole = mass of substance (g)/molar mass of substance (g/mol)

Molar mass of salicylic acid (C7H6O3) = 12(7) + 1(6) + 16(3)

= 84 + 6 + 48

= 138g/mol

Mass = 5.50grams

mole = 5.5/138

mole = 0.039

Approximately, the number of moles of 5.5grams of salicylic acid is 0.04moles. This is in accordance with the mole value (0.04) given in this question.

7 0
3 years ago
Which of these can be mined from earth and used as an energy source?
Nastasia [14]

coal

Which of these can be mined from earth and used as an energy source?

A.Get rid of the waste and extra fluid

B.Ureters

C.Coal

D.Bladder

ans is coal

4 0
3 years ago
4Al(s) + 3O2(g) 2Al2O3 (s) How many molecules of O2 are used in the reaction?
lutik1710 [3]
3 molecules of O2 are used in this reaction.

Hope this helps!
6 0
3 years ago
Write and the integrated rate laws hor zeroth-first- second-order rate laws.
Snowcat [4.5K]

Explanation:

The integrated rate law for the zeroth order reaction is:

[A]=-kt+[A]_0

The integrated rate law for the first order reaction is:

[A]=[A]_0e^{-kt}

The integrated rate law for the second order reaction is:

\frac{1}{[A]}=kt+\frac{1}{[A]_0}

Where,

[A] is the active concentration of A at time t

[A]_0 is the active initial concentration of A

t is the time

k is the rate constant

6 0
3 years ago
Read 2 more answers
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