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Alik [6]
2 years ago
12

How are distant regions of the universe similar to space near earth

Chemistry
1 answer:
Sergeu [11.5K]2 years ago
3 0
<span>The distant regions of the Universe look older than the space near the Earth. The more distant are, the older is. But the information we can have is lesser due to the distance.</span>
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One method used commercially to peel potatoes is to soak them in a solution of NaOH for a short time and then remove them from t
sergij07 [2.7K]

Answer:

b. 2.28 M

Explanation:

The reaction of neutralization of NaOH with H2SO4 is:

2NaOH + H2SO4 → Na2SO4 + 2H2O

<em>Where 2 moles of NaOH react per mole of H2SO4</em>

<em />

To solve the concentration of NaOH we need to find the moles of H2SO4. Using the chemical equation we can find the moles of NaOH that react and with the volume the molar concentration as follows:

<em>Moles H2SO4:</em>

45.7mL = 0.0457L * (0.500mol/L) = 0.02285 moles H2SO4

<em>Moles NaOH:</em>

0.02285 moles H2SO4 * (2moles NaOH / 1 mol H2SO4) = 0.0457moles NaOH

<em>Molarity NaOH:</em>

0.0457moles NaOH / 0.020L =

2.28M

Right option:

<h3>b. 2.28 M</h3>
7 0
2 years ago
Which formulas could represent the empirical formula and the molecular formula of a given compound?
Alina [70]

Answer:

d

Explanation:

d

7 0
2 years ago
Picture below<br><br> need done by 2:30<br><br><br><br> thanks, God bless your week
Leviafan [203]

1. \sf \bf {\boxed {\mathbb {Evaporation}}} - The changing of liquid to a gas.

2. \sf \bf {\boxed {\mathbb {Automobile}}} - The major source of pollution.

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4. \sf \bf {\boxed {\mathbb {Ozonosphere}}} - Layer absorbing ultraviolet rays.

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\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

5 0
2 years ago
Read 2 more answers
A 40.0 L balloon is filled with air at sea level (1 atm @ 25 oC). It is then tied to a rock and thrown into a cold lake and it s
velikii [3]
To solve this question you need to calculate the number of the gas molecule. The calculation would be:
PV=nRT
n=PV/RT
n= 1 atm * 40 L/ (0.082 L atm mol-1K-<span>1 * 298.15K)
</span>n= 1.636 moles

The volume at bottom of the lake would be:
PV=nRT
V= nRT/P
V= (1.636 mol * 277.15K* 0.082 L atm mol-1K-1 )/ 11 atm= <span>3.38 L</span>
8 0
2 years ago
Help me 20 points please someone just get this done
faust18 [17]

Answer:

whut done

Explanation:

I ain't see nothing

6 0
3 years ago
Read 2 more answers
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