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Dafna11 [192]
3 years ago
12

What is the coefficient for this formula? 9 NaCl2 A. 11 B. 9 C. 2 D. 1

Chemistry
1 answer:
KATRIN_1 [288]3 years ago
5 0

Answer:

B. 9

Explanation:

The formula of the compound is given as:

            9NaCl

Coefficient is the number before the compound. The compound here is made up of sodium and chlorine.

Therefore, we have 9 as the coefficient and it is 9 moles of NaCl.

  • The compound have 1 atoms of Na
  • Also 1 atom of Cl

Note, NaCl is an ionic compound.

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25 °C = ________ K <br><br> which one <br> 298<br> 0<br> 33 <br> 197
Paraphin [41]

Answer:

298

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Explanation:

5 0
3 years ago
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8. Bring the balloon in contact with the wall. What happens to the charges in the wall?
Ne4ueva [31]

When the charged balloon is brought near the wall, it repels some of the negatively charged electrons in that part of the wall. Therefore, that part of the wall is left repelled.

<u>Explanation</u>:  

  • Balloons don't stick to walls. However, if you rub the balloon on an appropriate piece of material such as clothing or a wall, electrons are pulled from the other material to the balloon.
  • The balloon now as more electrons than normal and therefore has an overall negative charge. Two balloons like this will repel each other.
  • The other material now has an overall positive charge. Because opposite charges attract, the balloon will now appear to stick to the other material. If you didn't rub the balloon first, it's charge would be neutral and it wouldn't stick to the wall.
7 0
4 years ago
The difference in composition between a weak base and its conjugate acid is
Svetach [21]
A weak Bronsted-Lowry base is a weak proton acceptor, where the proton is in the form of H+, so the conjugate acid formed contains one more H atom and an extra positive charge.
Hope this helps!
3 0
3 years ago
Why do populations of bacteria in nature eventually stop growing
LekaFEV [45]
They run out of nutrients or supplies. such as other organisms
8 0
3 years ago
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A phosphate buffer is involved in the formation of urine. The developing urine contains H2PO4 and HPO42- in the same concentrati
Katen [24]

Answer:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

Explanation:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

As the Bronsted definition sais, an acid is a substance with the ability to give protons thus, H2PO4 is the acid and HPO42- is the conjugate base.

The Ka expression is the ratio between the concentration of products and reactants of the equilibrium reaction so,

Ka = \frac{[HPO_{4}^{-2}] [H_{3}O^{+}]}{[H_{2}PO_{4}^{-}] [H_{2}O]} = 6.2x10^{-8}

The pKa is

-Log (Ka) = -Log (6.2x10^{-8}) = 7.2

The pKa of H2CO3 is 6,35, thus this a stronger acid than H2PO4. The higher the pKa of an acid greater the capacity to donate protons.

In the body H2CO3 is a more optimal buffer for regulating pH due to the combination of the two acid-base equilibriums and the two pKa.

If the urine is acidified, according to Le Chatlier's Principle the equilibrium (1)  moves to the left neutralizing the excess proton concentration.

3 0
4 years ago
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