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malfutka [58]
4 years ago
7

Please help me with this question

Mathematics
1 answer:
vlabodo [156]4 years ago
4 0

Answer:

72

Step-by-step explanation:

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What are the mean, median, and mode of the following data set? 3/4 2/5 1/10 3/4 1/4 a. mean: 1/10, median: 1/10, mode: 3/4 b. me
steposvetlana [31]
Mean: 9/20
Mode: 3/4 
Median: 2/4
3 0
3 years ago
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What is the fully factored form of 32a^3 + 12a^2?
Klio2033 [76]

<u>Answer:</u>

4a^{2} (8a + 3)

<u>Step-by-step explanation:</u>

32a^3 + 12a^2

To factorize this, start by taking the common variable out. As we have two powers for the same variable a, we can take the smaller power of a as a common to get like shown below:

32a^3 + 12a^2

a^2 (32a + 12)

Now when you have taken the variable as a common, try and take out a common number from the coefficient of a as well:

a^2 (32a + 12)

4a^2 (8a + 3)

So, the fully factored form of 32a^3 + 12a^2 is 4a^2 (8a + 3).

7 0
4 years ago
Rina’s recipe uses 2 cups of sugar to make 2 ½ dozen cookies. Jonah’s recipe uses 2 ¼ cups of sugar to make 3 dozen cookies. Whi
WITCHER [35]

Answer:

Let's calculate the "cups of sugar per dozen cookies" ratio:

2 cups

---------- = 0.8  (Rina)        

  2.5                                  

2.25 cups

------------- = 0.75 (Jonah)

     3

Rina uses more sugar for a dozen cookies.

8 0
3 years ago
Solve:
mash [69]

Answer:

1. Infinitely Many Solutions

2. Zero Solutions

3. One Solution ( x = 6 )

Step-by-step explanation:

1.

12x + 8 = 2( 6x + 4 )

12x + 8 = 12x + 8

2.

2( 2x + 1 ) = 4x + 3

4x + 2 = 4x + 3

2 = 3

3.

4( x + 1 ) = 3x + 10

4x + 4 = 3x + 10

x + 4 = 10

x = 6

Hopefully this helps!

Brainliest please?

8 0
3 years ago
Find the lower quartile from the set of data below.<br> 7,9, 9, 10, 14, 17, 20
KengaRu [80]

Answer:

7,9,9

Step-by-step explanation:

Because the numbers are lined up from least to greatest all you have to do is find the middle of all the numbers which is 10. So everything below ten is lower quartile. Everything above is upper quartile

5 0
3 years ago
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