Please help me with this question

Mathematics

1 answer:

vlabodo [156]3 years ago

4 0

Answer:

Step-by-step explanation:

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Nadusha1986 [10]

Answer: the answer is 0.04

Step-by-step explanation:

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3 years ago

There are 320 sixth grade students at Median Middle School. The school is hosting a field trip and 45% of the students are going

ratelena [41]

Answer:

the answer is 144

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4 0

3 years ago

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The total of 36 78 198 475 and 620

Alina [70]

The total of,
36
78
198
475
+620
-------
=1407

Hope this helps!=)

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3 years ago

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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$