Answer:
Power brake is a device in vehicles which assists in braking by reducing the effort/force needed to apply the brakes on the pedal.
This question is incomplete, the complete question is;
When an auditorium has a solid wall, sound waves will tend to perfectly reflect off the wall (i.e. with a 180o phase change). If listening to music, as from an orchestra, the incoming and reflected waves will interfere with each other. For a listener sitting 0.5 m from the wall, what is the lowest frequency which gets suppressed by this interference? Use vsound=330 m/s.
Answer: f = 165 Hz
the lowest frequency which gets suppressed by this interference is 165 Hz
Explanation:
For a reflected wave (out of phase), the path difference between the incoming and reflected wave should be equal to the half integral multiple of wavelength.
r₂ - r₁ = ( m + 1/2) λ/2
r₂ is the distance from the source to observer via reflection
r₁ is distance from source to observer
here r₂ would travel an additional distance of 0.5 m due to reflection that straight approaching wave.
Therefor to have minimum/lowest possible frequency, we say m = 0
we substitute
0.5 = ( 0 + 1/2 ) λ/2
λ = 2m
The frequency would be
f = Vsound / λ
f = 330 / 2
f = 165 Hz
Therefore the lowest frequency which gets suppressed by this interference is 165 Hz
Answer:
no:
Explanation:
it would grow and no longer be able to fit through the loop due to the hot air expanding.
Answer:
v(t) = 27 units
Explanation:
The function s(t) represents the position of an object at time t moving along a line such that,
and
We need to find the average velocity of the object over the interval of time [2,6]. The velocity of the object is equal to the total distance divided by time. It is given by :
v(t) = 27 units
So, the average velocity of the object is 27 units. Hence, this is the required solution.
Explanation:
It is known that the molecular weight of ammonia () is as follows.
Molecular weight () = = 17
(a) Therefore, we will calculate the mass as follows.
= 8500 g
Now, formula to calculate weight of the system in N is as follows.
Weight = mass × g
=
= 83.3 N (1 = 1 N)
Hence, the weight of the system is 83.3 N.
(b) Relation between specific volume and number of moles is as follows.
Therefore, calculate the specific volume as follows.
= 12
Also,
v =
= 0.705882
Therefore, we can conclude that the value of specific volume is 12 and 0.705882 .