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Elan Coil [88]
3 years ago
9

Jordan exercises one to two times a week. She usually works out alone. Between meals, she sometimes snacks on potato chips from

the bag. Which suggestion would least improve Jordan's overall fitness? A. exercise with friends or join a team B. eat snacks from a smaller-sized bag C. increase exercise frequency D. eat more meals at restaurants
Physics
1 answer:
tamaranim1 [39]3 years ago
8 0

C I think I (hope this Helps)


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Find the energy released when there is a decrease of 0.3kg of material in a nuclear reaction
MrRissso [65]

Answer:

E = 2.7 x 10¹⁶ J

Explanation:

The release of energy associated with the mass can be calculated by Einstein's mass-energy relation, as follows:

E = mc^2

where,

E = Energy Released = ?

m = mass of material reduced = 0.3 kg

c = speed of light = 3 x 10⁸ m/s

Therefore,

E = (0.3\ kg)(3\ x\ 10^8\ m/s)^2

<u>E = 2.7 x 10¹⁶ J</u>

4 0
3 years ago
Large amplitude of sound vibrations will produce.....
user100 [1]

Answer:

louder sound.

Explanation:

The amplitude of a sound wave determines its loudness or volume. A larger amplitude means a louder sound

8 0
3 years ago
How long does a car (1000 kg) have a speed of 30 m/s from a rest if the engine power is 10kw
Lemur [1.5K]

Answer: 90.1 s

Explanation:

Use equation for power:

P=F*V

Use eqation for force:

F=ma

F---force

V---velocity

Vr=om/s

V=30m/s

m=1000kg

P=10000W

---------------------------

P=FV

F=P/V

F=10000W/30m/s

F=333.33N

Use equation for force to find accelartaion.

F=ma

a=F/m

a=333.33N/1000kg

a=0.333 m/s²

Use equation for accelaration to find out time:

a=(V-Vs)/t

t=(V-Vs)/a

t=(30m/s)/(0.333m/s²)

t=90.09 s≈90.1 s

------------------------

5 0
3 years ago
A simple pendulum is made by tying a 2.44 kg stone to a string 4.57 m long. The stone is projected perpendicularly to the string
alexdok [17]

Answer:

v_{max}=8.2226m/s

Explanation:

The problem is solved using the law of conservation of energy,

So

mgL(1-cos\theta)+\frac{1}{2}mv^2_0=\frac{1}{2}mv^2_{max}

v_{max}=\sqrt{2gL(1-cos\theta)+v^2_0}

v_{max}=\sqrt{2(9.8)(4.57)(1-cos(69.4))+8^2}

v_{max}=8.2226m/s

8 0
3 years ago
Dimension equation of work
kkurt [141]

Answer:

Explanation:

Work

Other units Foot-pound, Erg

In SI base units 1 kg⋅m2⋅s−2

Derivations from other quantities W = F ⋅ s W = τ θ

Dimension M L2 T−2

Idk if this is what u are looking for but i hope this help.:)

3 0
3 years ago
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