m = mass of the ice added = ?
M = mass of water = 1.90 kg
= specific heat of the water = 4186 J/(kg ⁰C)
= specific heat of the ice = 2000 J/(kg ⁰C)
= latent heat of fusion of ice to water = 3.35 x 10⁵ J/kg
= initial temperature of ice = 0 ⁰C
= initial temperature of water = 79 ⁰C
T = final equilibrium temperature = 8 ⁰C
using conservation of heat
Heat gained by ice = Heat lost by water
m (T - ) + m = M ( - T)
inserting the values
m (4186) (8 - 0) + m (3.35 x 10⁵ ) = (1.90) (4186) (79 - 8)
m = 1.53 kg
If<span> a neutral </span>object loses<span> some </span>electrons<span>, </span>then<span> it will possess more protons</span>
Answer:
As an additional security measure in an AA&E storage facilities, securing drainage structures must be considered if their cross section is greater than 96 inches and any dimension is greater than 6 inches, they must be barred and welded at the intersections to prevent any human from crawling into the area.
Explanation:
U.S. national security relys on ensuring DoD sensitive or classified assets such as classified material, arms, ammunition, and explosives (AA&E) and nuclear weapons, in properly safeguard facilites and storage containers, voiding DoD assets loss or compromise and additional to supplemental intrusion detection systems and guard
patrols, security lighting, communications, fences and clear zones, drainage structures, key control, and other security measures required to protect AA&E.
Answer:
I don't know
Explanation:
I think it's at the highest, learned this in seventh grade
Answer:
F = 1280 N
Explanation:
Given that,
Acceleration experienced by a space shuttle, a = 32 m/s²
Mass of the astronauts, m = 40 kg
We need to find the force experienced by the astronaut.
We know that the net force is equal to the product of acceleration and its mass. So,
F = ma
F = 40 kg × 32 m/s²
So,
F = 1280 N
So, 1280 N of force is experienced by the Astronaut.
