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rewona [7]
3 years ago
7

Pace left home at 8 AM to spend the day at an amusement park. He arrived at the park, which was 150 km from his house, at 10 AM.

Pace explained that his speed was 38 km/h, which was a/an (accelerated / directional / instantaneous / average) speed, but the fastest speed he went was 60 km/h, which was a/an (directional / instantaneous / accelerated / average) speed.
Physics
1 answer:
arsen [322]3 years ago
3 0

Answer:

average speed, accelerated speed

Explanation:

Pace was first moving at 38 km/h which was his average speed but the fastest speed he went was 60 km/h so he accelerated.

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Answer : The average speed of the sprinter is, 34.95 Km/hr

Solution :

Average velocity : It is defined as the distance traveled by the time taken.

Formula used for average velocity :

v_{av}=\frac{d}{t}

where,

v_{av} = average velocity

d = distance traveled = 200 m

t = time taken = 20.6 s

Now put all the given values in the above formula, we get the average velocity of the sprinter.

v_{av}=\frac{200m}{20.6s}\times \frac{3600}{1000}=34.95Km/hr

conversion :

(1 Km = 1000m)

(1 hr = 3600 s)

Therefore, the average speed of the sprinter is, 34.95 Km/hr

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