The relationship between mass and acceleration is an inverse proportionality
Explanation:
The relationship between the acceleration of an object and its mass is given by Newton's second law, which states that:
where
F is the net force on the object
m is its mass
a is its acceleration
From the equation, we notice that if the force on the object is kept constant, then the mass and the acceleration are inversely proportional to each other. This means that:
- If the mass of the object is increased, its acceleration will decrease
- If the mass of the object is decreased, its acceleration will increase
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Answer:
The correct option is A = 1960 N/m²
Explanation:
Given that,
Mass m= 20,000kg
Area A = 100m²
Pressure different between top and bottom
Assume the plane has reached a cruising altitude and is not changing elevation. Then sum the forces in the vertical direction is given as
∑Fy = Wp + FL = 0
where
Wp = is the weight of the plane, and
FL is the lift pushing up on the plane.
Let solve for FL since the mass of the plane is given:
Wp + FL = 0
FL = -Wp
FL = -mg
FL = -20,000× -9.81
FL = 196,200N
FL should be positive since it is opposing the weight of the plane.
Let Equate FL to the pressure differential multiplied by the area of the wings:
FL = (Pb −Pt)⋅A
where Pb and Pt are the static pressures on bottom and top of the wings, respectively
FL = ∆P • A
∆P = FL/A
∆P = 196,200 / 100
∆P = 1962 N/m²
∆P ≈ 1960 N/m²
The pressure difference between the top and bottom surface of each wing when the airplane is in flight at a constant altitude is approximately 1960 N/m². Option A is correct
Answer:
a. Your mass with the basketball is 55.5 kg
b. Your new velocity is 0.045 m/s
Explanation:
We first add your weight and the basketballs weight to get 55.5 kg.
Then to find b. we use the equation: v final = (m1 * v1) / (m1 +m2)
So m1 is the basketball which is 0.5 kg and v1 is 5 m/s. So the top half is (0.5 * 5)
The bottom half is just our weights added together.
Answer:
0.00325 moles/liter/second
Explanation:
The tangent line has a slope of (y2 -y1)/(x2 -x1) = (0.35-0.48)/(40-0) = -0.00325.
The rate of the reaction is about 0.00325 moles/liter/second.
_____
This is the rate of decrease of the concentration of A.
