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True [87]
3 years ago
5

A substance whose shape can easily change is a

Physics
1 answer:
OleMash [197]3 years ago
8 0
There are many. But if this is a chemistry question it’s liquid
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Solid to gas stage changes are known as "sublimation." In many cases, solids transform into gases simply after an intermediate liquid state. It is an endothermic procedure (happens with the absorption of heat from the environment).  

Some example:

Freeze drying - Water can be sublimated in sustenance items by utilizing a vacuum.  

"Dry ice" or, in other words carbon dioxide and as the name proposes it experiences stage change from solid state to liquid state straightforwardly without wetting or going into liquid state.


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Which of these discoveries is generally attributed to kepler?
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The orbit of Mars is an ellipse,<span> is generally attributed to Kepler.
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What is the frequency of ultraviolet light?
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Jane puts some water into an electric kettle and then she connects it to the power source. She observes that after some time the
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C) electrical energy is transformed into heat energy
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Given a particle that has the velocity v(t) = 3 cos(mt) = 3 cos (0.5t) meters, a. Find the acceleration at 3 seconds. b. Find th
DiKsa [7]

Answer:

a.\rm -1.49\ m/s^2.

b. \rm 50.49\ m.

Explanation:

<u>Given:</u>

  • Velocity of the particle, v(t) = 3 cos(mt) = 3 cos (0.5t) .

<h2>(a):</h2>

The acceleration of the particle at a time is defined as the rate of change of velocity of the particle at that time.

\rm a = \dfrac{dv}{dt}\\=\dfrac{d}{dt}(3\cos(0.5\ t ))\\=3(-0.5\sin(0.5\ t.))\\=-1.5\sin(0.5\ t).

At time t = 3 seconds,

\rm a=-1.5\sin(0.5\times 3)=-1.49\ m/s^2.

<u>Note</u>:<em> The arguments of the sine is calculated in unit of radian and not in degree.</em>

<h2>(b):</h2>

The velocity of the particle at some is defined as the rate of change of the position of the particle.

\rm v = \dfrac{dr}{dt}.\\\therefore dr = vdt\Rightarrow \int dr=\int v\ dt.

For the time interval of 2 seconds,

\rm \int\limits^2_0 dr=\int\limits^2_0 v\ dt\\r(t=2)-r(t=0)=\int\limits^2_0 3\cos(0.5\ t)\ dt

The term of the left is the displacement of the particle in time interval of 2 seconds, therefore,

\Delta r=3\ \left (\dfrac{\sin(0.5\ t)}{0.05} \right )\limits^2_0\\=3\ \left (\dfrac{\sin(0.5\times 2)-sin(0.5\times 0)}{0.05} \right )\\=3\ \left (\dfrac{\sin(1.0)}{0.05} \right )\\=50.49\ m.

It is the displacement of the particle in 2 seconds.

7 0
3 years ago
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