There are 1.456 moles of hydrogen in 5.2 moles of C7H18
The number of mole of nitrogen gas, N₂, needed to produce 150 g of ammonia, NH₃ is 4.41 moles
<h3>How to determine the mole of NH₃ produced </h3>
- Mass of NH₃ = 150 g
- Molar mass of NH₃ = 14 + (3×1) = 17 g/mol
Mole = mass /molar mass
Mole of NH₃ = 150 / 17
Mole of NH₃ = 8.82 moles
<h3>How to determine the mole of N₂ needed </h3>
Balanced equation
N₂ + 3H₂ —> 2NH₃
From the balanced equation above,
2 moles of NH₃ were produced by 1 mole of N₂.
Therefore,
8.82 moles of NH₃ will be produced by = 8.82 / 2 = 4.41 moles of N₂.
Thus, 4.41 moles of N₂ is needed for the reaction.
Learn more about stoichiometry:
brainly.com/question/14735801
<span>In a reaction progress curve, each peak of the curve corresponds to the activation energy of the reaction.</span>
Answer: Molar heat of solution for the salt is 2563 kJ/mol
Explanation:
Let the heat absorbed during reaction be q.

q = Heat gained by solution = ?
m = Mass of water + mass of salt = 100.000 g + 5.556 g = 105.556 g
c = Heat capacity of solution = Heat capacity of water = 4.184 J/g°C
Change in temperature = ΔT = (80.000°C-11.517°C) = 68.483°C


0.01180 moles of salt absorbs = 30245.3 J
1 mole of salt absorbs =
of heat
Thus molar heat of solution for the salt in kJ/mol is 2563
Answer:
The concentration of HA is the same as concentration of H3O+ and A- produced.
Explanation:
The dissociation equation is given below:
HA(aq) + H2O (l) —> H3O+(aq) + A-(aq)
From the reaction above, we can see that the acid is monoprotic acid i.e it has only 1 ionisable hydrogen atom.
Now, from the balanced equation, we can see that the acid produced equal concentration of H3O+ and A-.
This account for the reason why the bars for H3O+ and A- have the same height as the bar for HA.