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mote1985 [20]
3 years ago
14

Selenium (Se) has 30 protons and 20 neutrons in each atom, therefore its atomic

Chemistry
1 answer:
allochka39001 [22]3 years ago
8 0

Answer:

30, 50

Explanation:

Hello,

In this since an element's atomic number is equal to the number of protons in its atom, we can infer that selenium's atomic number is 30. Moreover, due to the fact the the neutrons are equal to the atomic mass minus the atomic number or the number of protons, by knowing the number of neutrons we compute the atomic as follows:

neutrons=mass-protons\\\\mass=neutrons+protons\\\\mass=30+20\\\\mass=50a.m.u

Thus, answer is 30, 50.

Best regards.

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Why do larger gases such as Neon produce more color bands (line spectra) than smaller gases like Hydrogen?
LekaFEV [45]
Larger gases produces more spectral lines than the smaller gases because they have more orbitals in their atoms.
Hydrogen has only one orbital in which an electron orbits. At the excited state, that is, when the electron gains energy, the number of energy level it can transcend is very few. For larger elements, they have more orbitals and when excited, they can move from the ground state to other energy levels at which they produce various unique spectral lines.
7 0
3 years ago
would you like to explore outer space? Why or why not? If you could travel to any part of the galaxy at lightning speed would li
morpeh [17]

Answer:

Yes!

Explanation:

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4 0
3 years ago
Consider the followong balanced reaction. What mads in g of co2 can be formed from 288 mg of o2. Assume that there is excess c3h
Gwar [14]

<u>Answer:</u>

<em>0.264 g of CO_2 can be formed from 288 mg of O_2</em>

<u>Explanation:</u>

The balanced chemical equation is

2 C_3 H_7 OH+9 O_2> 6 CO_2+8 H_2 O

The conversions are  

Mass in mg O_2 is converted to mass in g O_2  

Mass in g O_2 is converted to moles O_2 by dividing with molar mass  

Moles O_2 is converted to moles CO_2  by using the mole ratio of O_2:CO_2 is 9 : 6

Moles CO_2  is converted to mass CO_2 by multiplying with molar mass CO_2

mass in mg O_2  > mass in g O_2 >moles O_2 > moles CO_2 > mass CO_2

288mg O_2 \times \frac{(1g O_2)}{(1000mg O_2 )} \times \frac {(1molO_2)}{(32gO_2 )}\times\frac {(6mol CO_2)}{(9mol O_2 )} \times \frac {(44.0 gCO_2)}{(1mol CO_2 )}

=0.264g (Answer)

7 0
3 years ago
Jade wants to measure the thickness of a copper wire. She wound the copper wire 30 times around a pencil and used a ruler to mea
Gala2k [10]

Answer: 0.05

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3 0
3 years ago
Read 2 more answers
Examine the chemical reaction and lab scenario.
Ierofanga [76]

Explanation:

Percentage Yield

= (3.37g/3.81g) * 100% = 88.45%.

Therefore 88.45% SO2 is the percentage yield.

3 0
3 years ago
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